像字符串拆分操作一样,根据行将文本文件分成块?

也许用 itertools.groupby :

import itertools

def bobo(x):    
    if x.startswith('BOBO:'):
        bobo.count+=1
    return bobo.count
bobo.count=0

with open('a') as f:
    for key,grp in itertools.groupby(f,bobo):
        print(key,list(grp))

(1, ['BOBO:12341234123412341234\n', '1234123412341234123412341\n', '123412341234\n'])
(2, ['BOBO:12349087609812340-98\n', '43690871234509875\n', '45\n', '\n'])
(3, ['BOBO:32498714235908713248\n', '0987235\n'])

import cStringIO
with open('a') as f:
    file_handles=[]
    for key,grp in itertools.groupby(f,bobo):
        file_handles.append(cStringIO.StringIO(''.join(grp)))

file_handles 将是一个类似文件的对象列表,每个“BOBO:”节一个。

subFileBlocks = []

with open('myReportFile.txt') as fh:
  for line in fh:
    if line.startswith('BOBO'):
      subFileBlocks.append(line)
    else:
      subFileBlocks[-1] += line

子文件块的末尾应该包含字符串形式的节。