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如何使用注释在hibernate中映射“映射”?

mapping orm hibernate java

Omar Kooheji · 技术社区 · 15 年前

使用注释如何将实体中的字段映射到给定对象,该实体是字符串的“映射”(哈希表)?对象已被注释,其实例已存储在hibernate数据库中。

<class name="Foo" table="foo">
    ...
    <map role="ages">
         <key column="id"/>
         <index column="name" type="string"/>
         <element column="age" type="string"/>
     </map>
 </class>

<class name="Foo" table="foo">
    ...
  <map role="ages">
    <key column="id"/>
    <index-many-to-many column="person_id" 
         class="Person"/>
    <element column="age" type="string"/>
  </map>
</class>
<class name="Person" table="person">
    ...
    <property name="name" column="name" 
         type="string"/>
</class>

但我不知道如何为一个简单的键到元素映射做到这一点,也不知道如何使用注释做到这一点。

4 回复 | 直到 10 年前

Pascal Thivent 15 年前

你可以简单地使用 @MapKey (请注意,JPA注释不同于Hibernate注释,即Hibernate注释 @MapKey

@javax.persistence.OneToMany(cascade = CascadeType.ALL)
@javax.persistence.MapKey(name = "name")
private Map<String, Person> nameToPerson = new HashMap<String, Person>();

whiskeysierra 15 年前

@CollectionOfElements(fetch = FetchType.LAZY)
@JoinTable(name = "JOINTABLE_NAME",
    joinColumns = @JoinColumn(name = "id"))
@MapKey(columns = @Column(name = "name"))
@Column(name = "age")
private Map<String, String> ages = new HashMap<String, String>();

Juan 8 年前

其他可能性如下:

@Entity
@Table(name = "PREFERENCE", uniqueConstraints = { @UniqueConstraint(columnNames = { "ID_DOMAIN", "ID_USER", "KEY" })})
public class Preferences {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "ID", unique = true, nullable = false)
    private Long id;

    @Column(name = "ID_DOMAIN", unique = false, nullable = false")
    private Long domainId;

    @Column (name = "PREFERENCE_KEY")
    @Enumerated(EnumType.STRING)
    private PreferenceKey key;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "ID_USER", referencedColumnName = "ID")
    private User user;
}

and 

@Entity
@Table(name = "USER", uniqueConstraints = { @UniqueConstraint(columnNames = { "ID_DOMAIN", "LOGIN" })})
public class User {
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "ID", unique = true, nullable = false)
    private Long id;

    @Column(name = "ID_DOMAIN", unique = false, nullable = false")
    private Long domainId;

    // more fields

    @ElementCollection(fetch = FetchType.LAZY)
    @JoinColumns({@JoinColumn(name = "ID_USER", referencedColumnName = "ID"), @JoinColumn(name = "ID_DOMAIN", referencedColumnName = "ID_DOMAIN")})
    @OneToMany(targetEntity = Preferences.class, fetch = FetchType.LAZY)
    @MapKey(name = "key")
    private Map<PreferenceKey, Preferences> preferencesMap;
}

这只生成两个表User和Preferences,请注意PreferenceKey对于域中的用户是唯一的

Jeff Walker 15 年前

您可能应该使用UserType或UserCollectionType。或者,您可以使用自定义tupleizer。

看见 hibernate core documentation 对于概念和 hibernate annotations documentation 对于等效注释方法。