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Sphinx4不会识别完整的语音,如果。wav文件持续时间长

sphinx4 cmusphinx voice-recognition speech-recognition java

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calvinjam · 技术社区 · 7 年前

我们正在做一个用户答案保存为的项目。wav文件并在之后进行计算。我们已经为每个问题创建了语法。有两个问题我们有一个识别问题。问题可能是相同的,因为对于这两个问题,用户必须讲大约7-8秒。

这是我们用于其中一个问题的语法文件;

#JSGF V1.0;grammar Question8; public <Question8> = (  one hundred | ninety three | eighty six | seventy nine | seventy two | sixty five) * ;

在这里,用户必须倒数7秒。如果我说得太快,它能很好地识别。当我慢慢地说,比如说,在说“一百”之后,等一秒钟,然后像这样一直讲到六十五,它只会认出一百,不会认出其他单词。

两个主要部分负责这些过程:

我们为麦克风创建的类;

public final class SpeechRecorder {
static Configuration configuration = new Configuration();
static Microphone mic = new Microphone(16000, 16, 1, true, true, false, 10, true, "average", 0, "default", 6400);

public static void startMic() {
    mic.initialize();
    mic.startRecording();
    mic.getAudioFormat();
    mic.getUtterance();
    System.out.println("Audio Format is" + mic.getAudioFormat());

}

public static void stopMic(String questionName) {
    mic.stopRecording();
    Utterance u = mic.getUtterance();

    try {
        u.save("Resources/Answers/" + questionName + ".wav", AudioFileFormat.Type.WAVE);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

public static String getAnswersOfSpeech(String question) throws IOException {
    Evaluation.disableLogMessages();
    configuration.setAcousticModelPath("resource:/edu/cmu/sphinx/models/en-us/en-us");
    configuration.setDictionaryPath("resource:/edu/cmu/sphinx/models/en-us/cmudict-en-us.dict");
    configuration.setGrammarPath("resource:/Grammer");
    configuration.setGrammarName(question);
    configuration.setUseGrammar(true);
    StreamSpeechRecognizer recognizer = new StreamSpeechRecognizer(configuration);
    recognizer.startRecognition(new FileInputStream("Resources/Answers/" + question + ".wav"));
    SpeechResult Result = recognizer.getResult();
    String speechWords = Result.getHypothesis();

    return speechWords;
}

public static String getSavedAnswer(int question) {

    return User.getAnswers(question);

}

}

这就是我们保存用户答案的地方。wav文件进入我们的资源。

btn_microphone.addActionListener(new ActionListener() {

        public void actionPerformed(ActionEvent e) {

            click++;
            if (click % 2 == 1) {
                SpeechRecorder.startMic();
                btn_microphone.setIcon(new ImageIcon("Resources/Images/record.png"));
            } else {
                SpeechRecorder.stopMic("Question" + Integer.toString(question));

                btn_Next.setVisible(true);
                btn_microphone.setIcon(new ImageIcon("Resources/Images/microphone.png"));

                lbl_speechAnswer.setVisible(true);
                try {
                    userAnswer = SpeechRecorder.getAnswersOfSpeech("Question" + Integer.toString(question));
                } catch (IOException e1) {
                    e1.printStackTrace();
                }

                if (userAnswer.equals("")) {
                    lbl_speechAnswer.setText(
                            "<html>No answer was given, click on microphone button to record again</html>");
                } else {
                    lbl_speechAnswer.setText("<html>Your answer is " + userAnswer
                            + ", click on microphone button to record again</html>");
                }
            }

        }

    });

我不知道我们怎样才能克服这个问题。如果有人能帮助我,我将不胜感激。

1 回复 | 直到 7 年前

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Nikolay Shmyrev 7 年前

您需要一个循环,如 transcriber demo :

    while ((result = recognizer.getResult()) != null) {
        System.out.format("Hypothesis: %s\n", result.getHypothesis());
    }
    recognizer.stopRecognition();