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如何导入特定联系人的电话号码?

  •  0
  • Zubair Younas  · 技术社区  · 7 年前

    我正在尝试读取使用联系人选取器选择的联系人的电话号码。 代码:

    //calling Contact Picker
    public void CPick(View v){
            Intent intent=new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
            startActivityForResult(intent, PICK_CONTACT);
        }
        @Override
    //Contact Picker here:
        protected void onActivityResult(int reqCode, int resultCode, Intent data){
            super.onActivityResult(reqCode,resultCode, data);
    
            if (reqCode==PICK_CONTACT){
                if(resultCode==AppCompatActivity.RESULT_OK){
                    Uri contatctData=data.getData();
                    Cursor c=getContentResolver().query(contatctData,null,null,null,null);
                    if (c.moveToFirst()){
                        //String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
    //Above line works Fine
    
                        String name=c.getString(c.getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER));
    //Above line gives error on runtime "invalid column"
                        Toast.makeText(this,"U have picked:"+name,Toast.LENGTH_SHORT).show();
    
    
    
                    }
                }
    
            }
        }
    

    任何帮助都将非常感谢,因为我在任何地方都找不到相关的答案。

    2 回复  |  直到 7 年前
        1
  •  1
  •   marmor    7 年前

    如果你想让用户选择一个电话号码,最好的选择是使用 PHONE-PICKER 不是一个 CONTACT-PICKER :

    Intent intent = new Intent(Intent.ACTION_PICK, CommonDataKinds.Phone.CONTENT_URI);
    startActivityForResult(intent, PICK_PHONE);
    
    ...
    
    protected void onActivityResult(int requestCode, int resultCode, Intent intent){
        if (requestCode == PICK_PHONE && resultCode == RESULT_OK){
            Uri phoneUri = intent.getData();
            Cursor cur = getContentResolver().query(phoneUri, new String[] { Phone.DISPLAY_NAME, Phone.NUMBER }, null, null, null);
            if (cur != null && cur.moveToFirst()){
                String name = cur.getString(0);
                String number = cur.getString(1);
                Log.d("PHONE-PICKER", "User picker: " + name + " - " + number);
                cur.close();
            }
        }
    }
    
        2
  •  1
  •   HyunJin    7 年前

    尝试以下方法:

    private void retrieveContactNumber() {
    
      String contactNumber = null;
    
      // getting contacts ID
      Cursor cursorID = getContentResolver().query(uriContact,
            new String[]{ContactsContract.Contacts._ID},
            null, null, null);
    
      if (cursorID.moveToFirst()) {
    
        contactId = cursorID.getString(cursorID.getColumnIndex(ContactsContract.Contacts._ID));
      }
    
      cursorID.close();
    
      Log.d(TAG, "Contact ID: " + contactId);
    
      // Using the contact ID now we will get contact phone number
      Cursor cursorPhone = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
            new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER},
    
            ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ? AND " +
                    ContactsContract.CommonDataKinds.Phone.TYPE + " = " +
                    ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE,
    
            new String[]{contactId}, null);
    
      if (cursorPhone.moveToFirst()) {
        contactNumber = cursorPhone.getString(cursorPhone.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
      }
    
      cursorPhone.close();
    
      Log.d(TAG, "Contact Phone Number: " + contactNumber);
    }
    

    你应该在日志中看到联系电话。