如何验证json的结构?

假设这是转换为python字典的json

ordered\u dict=[{'DeviceInstanceId':1,'IsResetNeeded':False,'ProductType':'testing','Product':{'Family':'12345','Model':“f10”,“Type”:“data”,“Vendor”:“qspi”}}]

您可以使用ordered\u dict.keys()按顺序获取所有键,现在因为它是一个字典列表,所以您必须获取所有项的键并相互比较,以检查所有键是否按顺序排列,我正在转换为元组的元组进行比较。

tuple_of_keys = tuple([tuple(j.keys()) for j in ordered_dict])

这将为您提供一组组密钥。

现在做一组元组,比如,

if len(set(tuple_of_keys)) == 1:
    print("all keys are in order")
else:
    print("missing data")

如果长度等于1,则所有键的顺序相同

要比较产品密钥中的密钥,请将代码更改为

tuple_of_keys = tuple([tuple(j['Product'].keys()) for j in ordered_dict])

并再次遵循相同的方法

如果要手动传递密钥顺序并检查顺序是否匹配,请使用以下代码。

order_of_keys = ('Vendor', 'Model', 'Type', 'Family')

ordered_dict = [{'DeviceInstanceId': 1, 'IsResetNeeded': False, 
'ProductType': 'testing', 'Product': {'Family': '12345',"Model": 
"f10","Type": "data","Vendor": "qspi"}},{'DeviceInstanceId': 1, 
'IsResetNeeded': False, 'ProductType': 'testing', 'Product': {'Family': 
'12345',"Model": "f10","Type": "data","Vendor": "qspi"}}]


def tests(order_of_keys,ordered_dict):
    tuple_of_keys = tuple([tuple(j['Product'].keys()) for j in ordered_dict])
    for each_item in tuple_of_keys:
        if each_item == order_of_keys:
            print("all keys are in order")
        else:
            print("missing data")
tests(order_of_keys,ordered_dict)