Java runtime.exec未正确执行

由于您的程序产生了大量输出,我的假设是,它无法写入标准输出(这是Linux下的管道,不适用于Windows)。

试试看:

final byte[] devnull = new byte[1024];

final ProcessBuilder builder = new ProcessBuilder("C:\\test.exe", "param1", "param2")
    .redirectErrorStream(true);
final Process p = builder.start();

final InputStream stdout = process.getInputStream();

// Purge stdout
while (stdout.read[devnull] != -1);

// Grab the process' exit code here

正如fge在 https://stackoverflow.com/a/21903969 ,重要的是要消耗该过程产生的所有输出,不仅是在Linux上,而且在Windows上,不仅是标准输出,还有可能的错误。

这方面的一般模式如下:

private static void runCommand(String command) throws IOException
{
    Process process = Runtime.getRuntime().exec(command);
    String errorMessage = 
        new String(toByteArray(process.getErrorStream()));
    String outputMessage = 
        new String(toByteArray(process.getInputStream()));
    int exitValue = 0;
    try
    {
        exitValue = process.waitFor();
    }
    catch (InterruptedException e)
    {
        Thread.currentThread().interrupt();
    }
    System.out.println("Output message: "+outputMessage);
    System.out.println("Error message: "+errorMessage);
    System.out.println("Exit value: "+exitValue);
}

private static byte[] toByteArray(
    InputStream inputStream) throws IOException
{
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    byte buffer[] = new byte[8192];
    while (true)
    {
        int read = inputStream.read(buffer);
        if (read == -1)
        {
            break;
        }
        baos.write(buffer, 0, read);
    }
    return baos.toByteArray();
}

"C:\test.exe param1 param2"

你有一个标签。试试看:

"C:\\test.exe param1 param2"

如果进程在stdout或stderr上生成任何输出,则需要使用它。否则它可能会阻塞。