具有无限生成器的赋值左侧

很抱歉把我先前的问题翻了一番,但我想问一些具体的数据,可以解决这个问题。我想要这个结果

tuple_of_vars = (item for _, item for zip(tuple_of_vars, new_vals_generator))

因为这是不可能的

a, b, c, d = (val for val in infite_generator)

实际上,我想排成一行

for var in var_list:
    var = next(infinite_generator)

还有一种方法可以使变量生成器成为赋值的左手边。

编辑:这不会在Python3中停止:

def incr(a):
    while True:
        yield a
        a += 1


a = [None for i in range(20)]

a[3:3:3], *_ = incr(1)

print(a)

同:

a,b,c,d, *_ = incr(1)

print(a, b, c, d)

即使它没有切片(实际上索引是变量,这只是测试)。我知道小岛等,但太慢了。

这也会产生错误:

a = 1000*[True]

bound = int(len(a) ** 0.5)

for i in range(3, bound, 2):
    a[3::i], *x = [[False] for _ in range(bound)]

""" Error:
ValueError: attempt to assign sequence of size 1 to extended slice of size 333
"""

而这个:

a = 1000*[True]

bound = int(len(a) ** 0.5)

for i in range(3, bound, 2):
    a[3::i], *x = [False] * bound

""" Error:
TypeError: must assign iterable to extended slice
"""