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如何为RustBox实现同步?

thread-safety rust multithreading

1

ritiek · 技术社区 · 9 年前

RustBox type 从 rustbox 板条箱在螺纹内。

我想按一下 q 键并显示 + 当我按下时,符号在(1,1)处持续2秒 w 在显示另一个的2秒内输入 + (1,2)处的符号。

我为相同的逻辑编写了一些代码:

extern crate rustbox;

use std::thread;
use std::time::Duration;

use rustbox::{Color, RustBox};
use rustbox::Key;


fn mark_at(x: usize, y: usize, rustbox: &RustBox) {
    rustbox.print(x, y, rustbox::RB_BOLD, Color::Black, Color::White, "+");
    thread::spawn(move || {
        let delay = Duration::from_millis(2000);
        thread::sleep(delay);
        rustbox.print(x, y, rustbox::RB_BOLD, Color::Black, Color::White, " ");
    });
}


fn main() {
    let rustbox = match RustBox::init(Default::default()) {
        Result::Ok(v) => v,
        Result::Err(e) => panic!("{}", e),
    };
    rustbox.print(1, 1, rustbox::RB_BOLD, Color::Black, Color::White, " ");
    rustbox.print(1, 2, rustbox::RB_BOLD, Color::Black, Color::White, " ");

    loop {
        rustbox.present();
        match rustbox.poll_event(false) {
            Ok(rustbox::Event::KeyEvent(key)) => {
                match key {
                    Key::Char('q') => {
                        mark_at(1, 1, &rustbox);
                    }
                    Key::Char('w') => {
                        mark_at(1, 2, &rustbox);
                    }
                    Key::Esc => { break; }
                    _ => { }
                }
            },
            Err(e) => panic!("{}", e),
            _ => { }
        }
    }
}

它给了我:

error[E0277]: the trait bound `*mut (): std::marker::Sync` is not satisfied in `rustbox::RustBox`
  --> src/main.rs:12:5
   |
12 |     thread::spawn(move || {
   |     ^^^^^^^^^^^^^ `*mut ()` cannot be shared between threads safely
   |
   = help: within `rustbox::RustBox`, the trait `std::marker::Sync` is not implemented for `*mut ()`
   = note: required because it appears within the type `std::marker::PhantomData<*mut ()>`
   = note: required because it appears within the type `rustbox::RustBox`
   = note: required because of the requirements on the impl of `std::marker::Send` for `&rustbox::RustBox`
   = note: required because it appears within the type `[closure@src/main.rs:12:19: 16:6 rustbox:&rustbox::RustBox, x:usize, y:usize]`
   = note: required by `std::thread::spawn`

error: aborting due to previous error

如何实施 Sync 对于 生锈的箱子 键入以使上述代码可以工作?

1 回复 | 直到 9 年前

1

ritiek 9 年前

RustBox 不执行 Send ,因此没有(安全的)方法在线程之间共享它(似乎您已经找到了尚未合并的pull请求) https://github.com/gchp/rustbox/pull/65 这将支持 邮寄 ).

生锈的箱子 在一个 Mutex ,即。 Mutex<RustBox> ,对它的引用可以在线程之间共享。

但接下来你会遇到终身问题:你的 rustbox 引用的寿命不够长,无法使用它生成新线程,因此您必须将其包装在 Arc .

use std::sync::{Arc,Mutex};

fn mark_at(x: usize, y: usize, rustbox: &Arc<Mutex<RustBox>>) {
    rustbox.lock().unwrap().print(x, y, rustbox::RB_BOLD, Color::Black, Color::White, "+");
    let rustbox = rustbox.clone(); // increment reference counter
    thread::spawn(move || {
        let delay = Duration::from_millis(2000);
        thread::sleep(delay);
        rustbox.lock().unwrap().print(x, y, rustbox::RB_BOLD, Color::Black, Color::White, " ");
    });
}

在你的 main 函数,您必须将 生锈的箱子 :

let rustbox = Arc::new(Mutex::new(rustbox));

和 lock() 每次你使用它。

确保锁不要放得太久;使用辅助变量可能有助于使其更明确,例如:

let pe = rustbox.lock().unwrap().poll_event(false);
match pe {
// ...
}