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Matplotlib:如何从列表中给定xticks值

histogram matplotlib python

0

SaadH · 技术社区 · 6 年前

我有以下代码:

import matplotlib.pyplot as plt
import numpy as np

xticks = ['A','B','C']
Scores = np.array([[5,7],[4,6],[8,3]])
colors = ['red','blue']
fig, ax = plt.subplots()
ax.hist(Scores,bins=3,density=True,histtype='bar',color=colors)
plt.show()

这将提供以下输出:

我有两个问题:

如何使条形图的高度表示中的值 Scores
如何跨x轴从指定值 xticks

3 回复 | 直到 5 年前

1

3

ImportanceOfBeingErnest 6 年前

import matplotlib.pyplot as plt
import numpy as np
import pandas as pd

xticks = ['A','B','C']
Scores = np.array([[5,7],[4,6],[8,3]])
colors = ['red','blue']
names = ["Cat", "Dog"]
fig, ax = plt.subplots()
pd.DataFrame(Scores, index=xticks, columns=names).plot.bar(color=colors, ax=ax)
plt.show()

如果单独使用matplotlib,会稍微复杂一些,因为每个列都需要单独绘制,

import matplotlib.pyplot as plt
import numpy as np

xticks = ['A','B','C']
Scores = np.array([[5,7],[4,6],[8,3]])
colors = ['red','blue']
names = ["Cat", "Dog"]

fig, ax = plt.subplots()

x = np.arange(len(Scores))
ax.bar(x-0.2, Scores[:,0], color=colors[0], width=0.4, label=names[0])
ax.bar(x+0.2, Scores[:,1], color=colors[1], width=0.4, label=names[1])
ax.set(xticks=x, xticklabels=xticks)
ax.legend()
plt.show()

2

1

Polkaguy6000 6 年前

import matplotlib.pyplot as plt
import numpy as np

xticks = ['A','B','C']
Scores = np.array([[5,7],[4,6],[8,3]])
colors = ['red','blue']
fig, ax = plt.subplots()

# Width of bars
w=.2

# Plot both separately
ax.bar([1,2,3],Scores[:,0],width=w,color=colors[0])
ax.bar(np.add([1,2,3],w),Scores[:,1],width=w,color=colors[1])

# Assumes you want ticks in the middle
ax.set_xticks(ticks=np.add([1,2,3],w/2))

ax.set_xticklabels(xticks)
plt.show()

3

0

Reedinationer 6 年前

plt.xticks(range(0, 6), ('A', 'A', 'B', 'B', 'C', 'C'))