按屏幕高度获取iphone型号xs max

我正在尝试为xs max定制设计。之前我只是通过检查main.bound.screen.height来识别设备,根据此站点,对于xs max: https://www.paintcodeapp.com/news/ultimate-guide-to-iphone-resolutions ,应该返回896.0,对吗?

xcode 10.0xs max模拟器返回812.0作为屏幕高度(xr也一样,它应该有相同的屏幕点)。知道怎么解决这个问题吗?

enum IPhone: String {
  case SE, normal, plus, X, XSMax

  init?(height: CGFloat) {
    switch height {
    case 568: self = .SE
    case 667: self = .normal
    case 736: self = .plus
    case 812: self = .X
    case 896: self = .XSMax
    default:
      return nil
    }
  }
}

struct Design {
  static var iPhone = IPhone(height: UIScreen.main.bounds.height)!
}

在视图控制器的viewdidLoad()中:

print("screen height: \(UIScreen.main.bounds.height), iPhone: \(Design.iPhone.rawValue)")