将字节为[]的函数从C#转换为C++[闭合]

我的函数有原始C#代码: 它们就像一个符咒,我将把它们转换成C++

    public static byte[] EncryptBlock(byte[] filebuffer)
    {
        int a, i, j, k, tmp;
        int[] key, box;
        byte[] cipher;

        key = new int[KeyBoxLength];
        box = new int[KeyBoxLength];
        cipher = new byte[filebuffer.Length];

        for (i = 0; i < KeyBoxLength; i++)
        {
            key[i] = XorContentLock[i % XorContentLock.Length];
            box[i] = i;
        }
        for (j = i = 0; i < KeyBoxLength; i++)
        {
            j = (j + box[i] + key[i]) % 256;
            tmp = box[i];
            box[i] = box[j];
            box[j] = tmp;
        }
        for (a = j = i = 0; i < filebuffer.Length; i++)
        {
            a++;
            a %= KeyBoxLength;
            j += box[a];
            j %= KeyBoxLength;
            tmp = box[a];
            box[a] = box[j];
            box[j] = tmp;
            k = box[((box[a] + box[j]) % KeyBoxLength)];
            cipher[i] = (byte)(filebuffer[i] ^ k);
        }
        return cipher;
    }

这就是它们在C++上的外观,但我不知道为什么会出现这些错误。

std::string Conversion::EncryptBlock(std::string& buffer)
{
    int32 a, i, j, k, tmp;
    int key[256];
    int box[256];
    BYTE* cipher = new BYTE[buffer.length];
    for (i = 0; i < KeyBoxLength; i++)
    {
        key[i] = XorFileLock[i % 16];
        box[i] = i;
    }
    for (j = i = 0; i < KeyBoxLength; i++)
    {
        j = (j + box[i] + key[i]) % 256;
        tmp = box[i];
        box[i] = box[j];
        box[j] = tmp;
    }
    for (a = j = i = 0; i < buffer.length; i++)
    {
        a++;
        a %= KeyBoxLength;
        j += box[a];
        j %= KeyBoxLength;
        tmp = box[a];
        box[a] = box[j];
        box[j] = tmp;
        k = box[((box[a] + box[j]) % KeyBoxLength)];
        cipher[i] = (byte)(buffer[i] ^ k);
    }
    std::string ret(reinterpret_cast< char const* >(cipher));
    delete[] cipher;

    return ret;
}

当我编译它时,我得到了:

那么,我做错了什么?请解释一下,为什么?它应该是怎样的? 另一个例子: