如何通过SIGTERM释放动态分配变量?

... HEADERS ...

int *var;

void child() {
  ... //some work
  free(var);
  exit(EXIT_SUCCESSFUL);
}

int main(void) {
  ...
  //allocate variable
  var = (int *) malloc(N*sizeof(int));
  ... //work with var

  for(int i; i<PROC_COUNT; i++) {
    pid_t child = fork();
    if(pid == 0) {
      child(); //main function of new proces
      break;
    }
    elseif(pid < 0) {
      //there is enormous problem -> kill every proces
      kill(0, SIGTERM);
      waitpid(0, NULL, 0); //wait for children
      free(var);
      exit(EXIT_FAILURE);
    }

  }
  free(var);
  return EXIT_SUCCESS;
}

当进程分叉时,所有变量也会被克隆。在常规情况下,var的所有副本都会被释放。

如果有错误 fork() ,我向所有创建的进程发送信号SIGTERM。我需要为SIGTERM编写信号处理程序,释放var并终止应用程序。然而,free()不是 signal safe function --所以我不应该调用它。但是如何释放()那个变量呢?

非常感谢你的回答。..

EDIT:valgrind还显示仍可达到的变量:

==5928== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 15 from 1)
==5928== malloc/free: in use at exit: 20 bytes in 1 blocks.
==5928== malloc/free: 1 allocs, 0 frees, 20 bytes allocated.
==5928== For counts of detected errors, rerun with: -v
==5928== searching for pointers to 1 not-freed blocks.
==5928== checked 49,164 bytes.