我想在不删除其内容的情况下将新输入附加到列表会话\U。我试试这个:
...
try:
SESSION_U.append(UNIQUES)
except NameError:
SESSION_U = []
SESSION_U.append(UNIQUES)
...
NameError
SESSION_U
列表将被创建并追加;第二次
try
编辑
# save string s submitted from form to list K:
K = []
s = self.request.get('sentence')
K.append(s)
# clean up K and create 2 new lists with unique items only and find their frequency
K = K[0].split('\r\n')
UNIQUES = f2(K)
COUNTS = lcount(K, UNIQUES)
# append UNIQUES and COUNTS TO session lists.
# Session lists should not be initialized with each new submission
SESSION_U.append(UNIQUES)
SESSION_C.append(COUNTS)
如果我把
SESSION_C
K = []
他们的内容在每次提交时都会被删除;如果没有,我会得到
. 我正在寻求有关处理这种情况的标准方法的帮助。非常感谢。(我在谷歌应用引擎工作)