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Wireshark未收到Scapy Modbus响应

modbus scapy wireshark

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bulkmoustache · 技术社区 · 12 年前

我在运行Wireshark的远程PLC上运行下面的代码示例。为什么我只能得到查询(我也应该得到响应)?似乎PLC发送了响应,因为Scapy的输出显示 Received 1 packets, got 1 answers, remaining 0 packets .

你知道为什么会这样吗?

我还使用Scapy的sniff()函数执行了嗅探,但结果是相同的(只获取查询)。

#! /usr/bin/env python

import logging
logging.getLogger("scapy").setLevel(1)

from scapy import *
from modLib import *

# IP for all transmissions
ip = IP(dst="192.168.10.131")

# Sets up the session with a TCP three-way handshake
# Send the syn, receive the syn/ack
tcp = TCP( flags = 'S', window = 65535, sport = RandShort(), dport = 502, options = [('MSS', 1360 ), ('NOP', 1), ('NOP', 1), ('SAckOK', '')])
synAck = sr1 ( ip / tcp )

# Send the ack
tcp.flags = 'A'
tcp.sport = synAck[TCP].dport
tcp.seq = synAck[TCP].ack
tcp.ack = synAck[TCP].seq + 1
tcp.options = ''
send( ip / tcp )

# Creates and sends the Modbus Read Holding Registers command packet
# Send the ack/push i.e. the request, receive the data i.e. the response
tcp.flags = 'AP'
adu = ModbusADU()
pdu = ModbusPDU03()
adu = adu / pdu
tcp = tcp / adu
data = sr1(( ip / tcp ), timeout = 2)
data.show()

# Acknowledges the response
# Ack the data response
# TODO: note, the 17 below should be replaced with a read packet length method...
tcp.flags = 'A'
tcp.seq = data[TCP].ack
tcp.ack = data[TCP] + 17
tcp.payload = ''
finAck = sr1( ip / tcp )

1 回复 | 直到 12 年前

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Pierre 12 年前

首先,您的代码中有一个bug(在原始版本中存在 http://www.digitalbond.com/scadapedia/security-controls/scapy-modbus-extensions/ ),您需要添加 .seq 在那里: tcp.ack = data[TCP].seq + 17 .

正如评论中所说,你可以写 tcp.ack = data[TCP].seq + len(data[TCP].payload) .

无论如何,对于您尝试做的那种事情,TCP堆栈的工作通常是无用的。

我会这样做:

from scapy import *
from modLib import *
import socket

sock = socket.socket()
sock.connect(("192.168.10.131", 502))
s = StreamSocket(sock, basecls=ModbusADU)

ans, unans = s.sr(ModbusADU()/ModbusPDU03())
ans.show()

这样做更好吗?