外部检查Java对象层次结构

如果您不知道包——只有类名,可以使用Spring框架来尝试:

List<Class> classes = new LinkedList<Class>();
PathMatchingResourcePatternResolver scanner = new 
    PathMatchingResourcePatternResolver();
// this should match the package and the class name. for example "*.Bar"
Resource[] resources = scanner.getResources(matchPattern); 

for (Resource resource : resources) {
    Class<?> clazz = getClassFromFileSystemResource(resource);
    classes.add(clazz);
}


public static Class getClassFromFileSystemResource(Resource resource) throws Exception {
    String resourceUri = resource.getURI().toString();
    // finding the fully qualified name of the class
    String classpathToResource = resourceUri.substring(resourceUri
            .indexOf("com"), resourceUri.indexOf(".class"));
    classpathToResource = classpathToResource.replace("/", ".");
    return Class.forName(classpathToResource);
}

上面的两个方法为您提供了名为“bar”的类的列表(它们可能不止一个!).

那就更容易了

expectedSuperclass.isAssignableFrom(yourClass);

是的,思考就是答案:

Class barClass = Class.forName("some.package.Bar"); // will throw a ClassNotFoundException if Bar is not a valid class name
Class fooClass = some.package.Foo.class;
assert fooClass.isAssignableFrom(barClass); // true means Bar extends (or implements) Foo