python-如何从单个列表中创建元组列表[重复]

zip

a_list = [3, 2, 1, 0, 5, 4]
tuple_list = [(x, y) for x, y in zip(a_list, a_list[1:])]

# [(3, 2), (2, 1), (1, 0), (0, 5), (5, 4)]

tuple_list = list(zip(a_list, a_list[1:]))

您也可以使用 zip

l = [3, 2, 1, 0, 5, 4]
print(list(zip(l, l[1:])))
# [(3, 2), (2, 1), (1, 0), (0, 5), (5, 4)]

list comprehension 以下内容:

a_list = [3, 2, 1, 0, 5, 4]
tuple_list = [(a_list[i], a_list[i+1]) for i in range(len(a_list)-1)]
print(tuple_list)

[(3, 2), (2, 1), (1, 0), (0, 5), (5, 4)]

itertools recipes

from itertools import tee

def pairwise(iterable):
    a, b = tee(iterable)
    next(b, None)
    return list(zip(a, b))

print(pairwise([1, 2, 3, 4])) # [(1, 2), (2, 3), (3, 4)]

list

>>> a = [3, 2, 1, 0, 5, 4]
>>> b = [(a[x], a[x+1]) for x in range(len(a))]
>>> print b
[(3, 2), (2, 1), (1, 0), (0, 5), (5, 4)]