在Google的Colab笔记本中,如何从Python文件调用函数?

编辑 :如果要导入本地模块,请编辑 sys.path 指向那个新目录。下面是一个笔记本示例: https://colab.research.google.com/notebook#fileId=1PtYW0hZit-B9y4PL978kV2ppJJPhjQua

原始回复 : 当然,这里有一个笔记本示例: https://colab.research.google.com/notebook#fileId=1KBrq8aAiy8vYIIUiTb5UHG9GKOdEMF3n

有两个单元格:第一个单元格定义 .py 包含要导入的函数的文件。

%%writefile example.py
def f():
  print 'This is a function defined in a Python source file.'

第二个单元使用 execfile 评估一下 .py公司 文件保存在笔记本的Python解释器中。

# Bring the file into the local Python environment.
execfile('example.py')

# Call the function defined in the file.
f()

请尝试此功能将功能从驱动器导入colab笔记本:

from google.colab import files
import zipfile, io, os

def upload_dir_file(case_f):
    # author: yasser mustafa, 21 March 2018  
    # case_f = 0 for uploading one File or Package(.py) and case_f = 1 for uploading one Zipped Directory
    uploaded = files.upload()    # to upload a Full Directory, please Zip it first (use WinZip)
    for fn in uploaded.keys():
        name = fn  #.encode('utf-8')
        #print('\nfile after encode', name)
        #name = io.BytesIO(uploaded[name])
    if case_f == 0:    # case of uploading 'One File only'
        print('\n file name: ', name)
        return name
    else:   # case of uploading a directory and its subdirectories and files
        zfile = zipfile.ZipFile(name, 'r')   # unzip the directory 
        zfile.extractall()
        for d in zfile.namelist():   # d = directory
            print('\n main directory name: ', d)
            return d
print('Done!')

然后执行以下两个步骤: 1-如果您有一个名为(package\u name.py)的文件,要将其上载到colab笔记本,请拨打:

file_name = upload_dir_file(0)

2-然后,导入您的包:

import package_name

注意:您可以使用相同的功能: 1-上传文件(csv、excel、pdf等):

file\u name=upload\u dir\u文件(0)

dir_name = upload_dir_file(1)

享受吧!

鲍勃·史密斯的答案无法在colab中运行。 最简单的方法是:

exec(open(filename).read())