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将数组映射为以奇数元素为键,偶数元素为值的对象

arrays javascript

Treycos · 技术社区 · 6 年前

这个标题应该是不言自明的。如何转动以下阵列:

[
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
]

进入下面的数组:

[
    {"Bargain": "deal"},
    {"Consistent": "Steady; regular"},
    {"Accurately": "a thing bought or offered for sale much more cheaply than is usual or expected."},
    {"Charge": "demand (an amount) as a price for a service rendered or goods supplied."}
]

解决方案可能很简单,但我找不到一个简单的方法来实现它。我试着制作两个独立的数组,在合并之前先去掉第一个数组中的奇数和第二个数组中的偶数,然后再过滤每个数组中的元素,但这看起来太过分了。

有没有一个简单的方法来实现它?

(是的,我知道“准确”的定义是……怪异的)

2 回复 | 直到 6 年前

adiga 6 年前

你可以使用 Array.from 这样地:

const input = [
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
]

const length = Math.ceil(input.length / 2)

const output = Array.from({ length }, (_, i) =>
   ({ [input[i*2]]: input[i*2+1] })
  );
  
console.log(output)

Taki 6 年前

你可以用一个简单的 for 循环:

const data = [
  "Bargain",
  "deal",
  "Consistent",
  "Steady; regular",
  "Accurately",
  "a thing bought or offered for sale much more cheaply than is usual or expected.",
  "Charge",
  "demand (an amount) as a price for a service rendered or goods supplied."
];

let result = [];

for (let i = 0; i < data.length; i += 2) {
  result.push({
    [data[i]]: data[i + 1]
  });
}

console.log(result);

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