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一对多关系核心数据获取数据

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  • PaFi  · 技术社区  · 8 年前

    关于这个话题有很多问题,但我无法让它发挥作用。

    在瓦迪亚的回答中,他通过两个重复的循环得到值:

    1. swift 3 - core data relationship - fetch data
    2. https://stackoverflow.com/a/43846785/8887336

    它对我的代码不起作用,我也不知道为什么。

    这是我的代码:

    import Foundation
    import CoreData
    
    struct HobbiesCollection {
      let typ: String
      let location: String
    }
    
    
    class LoadData{
      class func load(context: NSManagedObjectContext) {
        let persons = ["Owen", "Greg"]
        let futbal = HobbiesCollection(typ: "futbal", location: "stadium")
        let swimming = HobbiesCollection(typ: "swimming", location: "pool")
        let collection = [persons[0]: swimming, persons[1]: futbal]
    
        for x in collection {
          let person = Person(context: context)
          let hobbiesCD = Hobbies(context: context)
          person.name = x.key
          hobbiesCD.typ = x.value.typ
          hobbiesCD.location = x.value.location
    
          person.addToToHobbies(hobbiesCD)
    
          do {
            try context.save()
          } catch let error {
            print(error.localizedDescription)
          }
        }
    
        let fetch: NSFetchRequest<Person> = Person.fetchRequest()
        var result = [Person]()
        do {
          result = try context.fetch(fetch)
        } catch let error {
        print(error.localizedDescription)
        }
        for y in result {
          print("Persons:", y.name!)
          for x in y.toHobbies! {
            let location = x.location Error: "Value of type 'Any' has no member 'location'"
          }
        }
      }
    }
    

    我得到错误:

    “Any”类型的值没有成员“location”

    我的两个核心数据类:

    extension Person {
    
        @nonobjc public class func fetchRequest() -> NSFetchRequest<Person> {
            return NSFetchRequest<Person>(entityName: "Person")
        }
    
        @NSManaged public var name: String?
        @NSManaged public var toHobbies: NSSet?
    
    }
    
    // MARK: Generated accessors for toHobbies
    extension Person {
    
        @objc(addToHobbiesObject:)
        @NSManaged public func addToToHobbies(_ value: Hobbies)
    
        @objc(removeToHobbiesObject:)
        @NSManaged public func removeFromToHobbies(_ value: Hobbies)
    
        @objc(addToHobbies:)
        @NSManaged public func addToToHobbies(_ values: NSSet)
    
        @objc(removeToHobbies:)
        @NSManaged public func removeFromToHobbies(_ values: NSSet)
    
    }
    extension Hobbies {
    
        @nonobjc public class func fetchRequest() -> NSFetchRequest<Hobbies> {
            return NSFetchRequest<Hobbies>(entityName: "Hobbies")
        }
    
        @NSManaged public var typ: String?
        @NSManaged public var location: String?
        @NSManaged public var toPerson: Person?
    
    }
    

    还有一个关于谓词的问题。 如果执行如下谓词获取:

    取来谓词=NSPredicate(格式:“name=%@”,person1)

    如果在我的示例中我有多个爱好,那么是否可以使用location=stadium(例如,使用第二个谓词参数)获取所有爱好,以代替使用for循环查找location=stadium of person1的这些爱好?

    1 回复  |  直到 8 年前
        1
  •  1
  •   Joakim Danielson    8 年前

    to嗜好属性是Any的nset,所以您需要键入它或循环中的每个x。

    对于谓词,可以使用像tocampoies这样的关键路径。位置=%@