导入文字的txt文件并以单独的行打印文字

drop_words.txt:

one
two
three
four

然后:

with open('drop_words.txt', encoding='utf-8') as file:
    content = file.readlines()
    # you may also want to remove empty lines
    content = [l.strip() for l in content if l.strip()]
    print(", ".join(content), end = '')

输出:

one, two, three, four

如果把这些词包装在一起,你的意思是 ,你可以用 grouper 比如:

import itertools as IT

def grouper(n, iterable):
    iterable = iter(iterable)
    return iter(lambda: list(IT.islice(iterable, n)), [])

with open('list.txt', encoding='utf-8') as file:
    content = file.readlines()
    content = [l.strip() for l in content if l.strip()]
    print(", ".join(content))
    grouping = ", ".join(content)
    #creating a list out of the comma separated string
    grouping = grouping.split(",")
    # grouping the two elements
    print(list(grouper(2, list(grouping))))

one, two, three, four
[['one', ' two'], [' three', ' four']]

编辑2:

OP提到了连续10位数字的组合

wrap = 0
newLine = True
with open('list.txt', encoding='utf-8') as file:
    content = file.readlines()
    # you may also want to remove empty lines
    content = [l.strip() for l in content if l.strip()]
    for line in content:
        if wrap < 10:
            print("{}, " .format(line), end = '')
        else:
            if newLine:
                print("\n")
                newLine = not newLine
            print("{}, ".format(line), end='')
        wrap += 1

one, two, three, four, five, six, seven, eight, nine, ten, 

eleven, twelve, thirteen, fourteen, fifteen, sixteen, seventeen, eighteen, 

这可以完成打印名称的工作:

with open('drop_words.txt', encoding='utf-8') as f:
    words = [line for line.strip() in f]
    print(','.join(words))

def grouped(iterable, n):
    return zip(*[iter(iterable)]*n)

>>> grouped(word, 7)