我试着在同一张图上用
plot_ly
lapply
一旦情节分离,函数就失败了。遵循我使用的代码和步骤:
首先,生成样本并将其放入一个称为“data”的向量中:
sample = rnorm(2093)
data <- as.data.frame(matrix(sample, nrow=91, ncol=23))
name = c("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23")
最后,我使用“lapply”函数滚动数据:
fig <- plot_ly(data, x = ~data[1])
aux_list_1 <- lapply(seq_along(data), function(j){
fig <- fig %>% add_trace(y = ~data[[j]], name = name[j],type='scatter',mode = 'lines')
fig
})
fig
未指定跟踪类型:
阅读有关此跟踪类型的详细信息->
https://plot.ly/r/reference/#histogram
或者,当我运行“aux_list_1”时,这些图是分开的。
遵循完整代码:
sample = rnorm(2093)
data<- as.data.frame(matrix(random,nrow=91,ncol=23))
name = c("1","2","3","4","5","6","7","8","9","10","11","12","13","14","15","16","17","18","19","20","21","22","23")
fig <- plot_ly(data, x = ~data[1])
aux_list_1 <- lapply(seq_along(data), function(j){
fig <- fig %>% add_trace(y = ~data[[j]], name = name[j],type='scatter',mode = 'lines')
fig
})
fig