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在typescript中合并具有相同值的JSON数据

typescript angular json

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Keerthi Reddy Yeruva · 技术社区 · 7 年前

我有一个JSON数据,是从URL获取的。我想合并 相同的值 以下是示例数据。我在网上搜索过,但没有找到解决办法。我找到的只是 相同的键 .

  [ {
    "banana": [
      {
        "color": yellow,
        "size": "small"
      },
      {
        "size": "medium"
      },
      {
        "size": "large"
      }
    ],
    "process_name": "fruits"},{
    "carnivores": [
      {
        "name": "lion"
      },
      {
        "name": "tiger"
      },
      {
        "name": "chetah"
      },
      {
        "name": "dianosaur"
      }
    ],
    "process_name": "animal"}, {
    "apple": [
      {
        "color": red,
        "size": "large"
      }
    ],
    "process_name": "fruits"}]

我想合并 "process_name" :"fruits" 在下面的一个数组中,结果应该是

[{
"banana": [
  {
    "color": yellow,
    "size": "small"
  },
  {
    "size": "medium"
  },
  {
    "size": "large"
  }
],
"apple": [
  {
    "color": red,
    "size": "large"
  }
],
"process_name": "fruits"  }, {
"carnivores": [
  {
    "name": "lion"
  },
  {
    "name": "tiger"
  },
  {
    "name": "chetah"
  },
  {
    "name": "dianosaur"
  }
],
"process_name": "animal"}]

有人能帮忙吗?

1 回复 | 直到 7 年前

1

2

Cerberus 7 年前

// data definition
const json_before = [ {
  "banana": [
    {
      "color": "yellow",
      "size": "small"
    },
    {
      "size": "medium"
    },
    {
      "size": "large"
    }
  ],
  "process_name": "fruits"},
{
  "carnivores": [
    {
      "name": "lion"
    },
    {
      "name": "tiger"
    },
    {
      "name": "chetah"
    },
    {
      "name": "dianosaur"
    }
  ],
  "process_name": "animal"},
{
  "apple": [
    {
      "color": "red",
      "size": "large"
    }
  ],
  "process_name": "fruits"
}];

// processing
const json_after = json_before.reduce((arr, next) => {
  const exist = arr.find(el => el.process_name === next.process_name);
  if (exist) Object.assign(exist, next);
  else arr.push(next);
  return arr;
}, []);

// check
console.log(json_after);

reduce Object.assign Object.keys

console.log(json_before)