在Python中减少for循环是不可能的?

for n in range(6,0,-1):
    print n
# prints [6, 5, 4, 3, 2, 1]

现在已经很晚了,但我只想补充一点,有一种更优雅的方法:使用 reversed

for i in reversed(range(10)):
    print i

给予:

4
3
2
1
0

for n in range(6,0,-1)

这会给你 6,5,4,3,2,1

至于

for n in reversed(range(0,6))

会给你 5,4,3,2,1,0

for n in range(6,0,-1):
    print n

>>> range(6, 0, -1)
[6, 5, 4, 3, 2, 1]

0是条件值当此条件为真时,循环将继续执行。10是初始值。1是可以是简单减量的修饰符。

for number in reversed(range(0,10,1)):
print number;

晚到派对,但对于任何负责创建自己的或想了解其工作原理的人,以下是一个附加功能,可以根据所需的增量重新排列开始-停止值:

def RANGE(start, stop=None, increment=1):
    if stop is None:
        stop = start
        start = 1

    value_list = sorted([start, stop])

    if increment == 0:
        print('Error! Please enter nonzero increment value!')
    else:
        value_list = sorted([start, stop])
        if increment < 0:
            start = value_list[1]
            stop = value_list[0]
            while start >= stop:
                worker = start
                start += increment
                yield worker
        else:
            start = value_list[0]
            stop = value_list[1]
            while start < stop:
                worker = start
                start += increment
                yield worker

负增量:

for i in RANGE(1, 10, -1):
    print(i)

或者,当起止点颠倒时:

for i in RANGE(10, 1, -1):
    print(i)

输出:

10
9
8
7
6
5
4
3
2
1

常规增量:

for i in RANGE(1, 10):
    print(i)

输出:

1
2
3
4
5
6
7
8
9

零增量:

for i in RANGE(1, 10, 0):
    print(i)

输出:

'Error! Please enter nonzero increment value!'