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如何从布局容器触发react模式?

  •  0
  • AnApprentice  · 技术社区  · 7 年前

    react-modal 在我的React+Redux+ReactRouter4应用程序中。

    我有一个主布局容器和一个主布局容器。

    只有在呈现主容器时才会使用模态,因此我在主容器中有ReactModal的逻辑。我可以很容易地从主容器中打开modal,如下所示:

    <button onClick={this.openModal}>Open Modal</button>
    

    class Home extends React.Component {
    
      constructor(props) {
        super(props);
        this.state = {
          modalIsOpen: false
        };
        this.openModal = this.openModal.bind(this);
        this.closeModal = this.closeModal.bind(this);
    
      }
    
      openModal() {
        this.setState({modalIsOpen: true});
      }
    
      closeModal() {
        this.setState({modalIsOpen: false});
      }
    
      render() {
        return (
          <div>
            ....
            <button onClick={this.openModal}>Open Modal</button>
    
            <Modal
              isOpen={this.state.modalIsOpen}
              onAfterOpen={this.afterOpenModal}
              onRequestClose={this.closeModal}
              style={modalCustomStyles}
              contentLabel="Example Modal"
            >
              <h2 ref={subtitle => this.subtitle = subtitle}>Hi</h2>
              <button onClick={this.closeModal}>close</button>
              <div>I am a modal</div>
            </Modal>
    
          </div>
        )
      };
    
    };
    

    App.jsx

    const WithMainLayout = ({component: Component, ...more}) => {
      return <Route {...more} render={props => {
        return (
          <MainLayout {...props}>
            <Component {...props} />
          </MainLayout>
        );
      }}/>;
    };    
    ....
    <WithMainLayout exact path="/" component={Home} />
    
    1 回复  |  直到 7 年前
        1
  •  1
  •   Ravindra Ranwala    7 年前

    我要做的是将modalOpenState迁移到redux,而不是将其保留在本地。你的初始状态是这样的。

    export default {
      modalIsOpen: false
    };
    

    然后编写一个操作来切换存储中的模式状态。

    export function toggleQuestionModal(isOpen) {
      return { type: types.TOGGLE_QUESTION_MODAL, payload: isOpen };
    }
    

    模态的表示组件应该是这样的。

    import React, { Component, PropTypes } from 'react';
    import Modal from 'react-modal';
    
    const QuestionModal = ({ modalIsOpen, openModal, closeModal, afterOpenModal }) => {
      const customStyles = {
        overlay: {
          position: 'fixed',
          top: 0,
          left: 0,
          right: 0,
          bottom: 0,
          backgroundColor: 'rgba(0, 0, 0, 0.75)'
        },
    
        content: {
          top: '50%',
          left: '50%',
          right: 'auto',
          bottom: 'auto',
          marginRight: '-50%',
          height: '50%',
          width: '80%',
          transform: 'translate(-50%, -50%)'
        }
      };
    
      return (
        <div>
          <button onClick={openModal}>Open Modal</button>
          <Modal
            isOpen={modalIsOpen}
            onAfterOpen={afterOpenModal}
            onRequestClose={closeModal}
            style={customStyles}
            contentLabel="Create A Question"
            role="dialog"
          >
    
            <h2>Hello</h2>
            <button onClick={closeModal}>close</button>
            <div>I am a modal</div>
            <form>
              <input />
              <button>tab navigation</button>
              <button>stays</button>
              <button>inside</button>
              <button>the modal</button>
            </form>
          </Modal>
        </div>
      );
    };
    
    QuestionModal.propTypes = {
      modalIsOpen: PropTypes.bool.isRequired,
      openModal: PropTypes.func.isRequired,
      closeModal: PropTypes.func.isRequired,
      afterOpenModal: PropTypes.func.isRequired
    };
    
    export default QuestionModal;
    

    最后,这是用于模式的容器组件。

    import React, { Component, PropTypes } from 'react';
    import { connect } from 'react-redux';
    import { bindActionCreators } from 'redux';
    import { toggleQuestionModal, toggleConfirmation } from '../actions/questionActions';
    import QuestionModal from '../components/questionModal';
    
    class QuestionPage extends Component {
        constructor(props, context) {
            super(props, context);
            this.openModal = this.openModal.bind(this);
            this.closeModal = this.closeModal.bind(this);
            this.afterOpenModal = this.afterOpenModal.bind(this);
        }
    
    
        openModal() {
            this.props.toggleQuestionModal(true);
        }
    
        afterOpenModal() {
            // references are now sync'd and can be accessed. 
            // this.subtitle.style.color = '#f00';
        }
    
        closeModal() {
            this.props.toggleConfirmation(true);
        }
    
        render() {
            const { modalIsOpen } = this.props;
            return (
                <div>
                    <QuestionModal modalIsOpen={modalIsOpen} openModal={this.openModal} closeModal={this.closeModal} 
                    afterOpenModal={this.afterOpenModal} />
                </div>
            );
        }
    }
    
    QuestionPage.propTypes = {
        modalIsOpen: PropTypes.bool.isRequired,
        toggleQuestionModal: PropTypes.func.isRequired,
    };
    
    function mapStateToProps(state, ownProps) {
        return {
            modalIsOpen: state.question.modalIsOpen
        };
    }
    
    function mapDispatchToProps(dispatch) {
        return {
            toggleQuestionModal: bindActionCreators(toggleQuestionModal, dispatch),
        };
    }
    
    export default connect(mapStateToProps, mapDispatchToProps)(QuestionPage);
    

    toggleQuestionModal 具有真实值的操作。这将更改状态并呈现模式。Redux建议将所有内容保持在状态。我确实练习过。不要把东西放在当地。将所有内容保持在状态下,可以更轻松地使用工具进行时间旅行调试。您可以找到示例实现 here 。希望这能有所帮助。快乐的编码!