jest-函数不调用其子异步函数

Login handleLoginSubmit 提交表单时调用的方法。这个方法实际上是在我的 store 登录

handleLoginSubmit = async (event) => {
    event.preventDefault();
    const result = await service.validateUser(this.username, this.password);
    if (result) {
        this.isAuthenticated = true;
        this.invalidLogin = false;
        history.push('/search');
    }
    else this.invalidLogin = true;
}

我已经编写了测试用例来检查 handleSubmit 提交表单时,以及验证是否正确:

describe('Login should authenticate users corectly when', () => {

    it('correct credentials are submitted', async () => {
        const spySubmit = jest.spyOn(store, 'handleLoginSubmit');
        const spyValidate = jest.spyOn(service, 'validateUser');
        const wrapper = shallow(<Login store={store} />);
        expect(spySubmit).toHaveBeenCalledTimes(0);
        wrapper.find('form').simulate('submit');
        expect(spySubmit).toHaveBeenCalledTimes(1);
        expect(spyValidate).toBeCalledWith({ username: store.username, password: store.password });
    });
});

服务.js:

export function validateUser(username, password) {
    return fetch(`https://abc.co/api?search=${username}`)
        .then(function (response) {
            return response.json();
        }).then(function (response) {
            if (response.results.length) {
                if (response.results[0].key === password) {
                    return true;
                }
                else return false;
            }
            else return false;
        });
}

service.validateUser 即使没有,也不会被调用 登录