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React Native无法在异步函数中正确设置超时

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  • Nino Filiu  · 技术社区  · 7 年前

    const someAction = async () => {
    
        // t=0s: logs 'one'
        console.log('one');
    
        // wait 1000ms for the promise to resolve
        await new Promise(resolve => setTimeout(resolve, 1000));
    
        // t=1s: logs 'two'
        console.log('two');
    
        // will log 'three' at t=2s
        setTimeout(() => console.log('three'), 1000);
    
    }
    


    #22620 #22620 和

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