如何在python字符串中的子字符串之间找到子字符串?

使用正则表达式。 re.findall 带lookback和Lookahead

import re
s = "AAAGQWERTYUIOPAGCTHJKLAAAGZXCVBNMAGCT"
print( re.findall(r"(?<=AAAG).*?(?=AGCT)", s))

['QWERTYUIOP', 'ZXCVBNM']

如果你不想使用正则表达式,那么我已经做了一个代码。这有点复杂,但如果你仔细看看,然后你就会明白。

def addd(llist,word,word2):
    xx1 = sum([[i, word] for i in llist], [])[:-1]
    try:iii = xx1.index(word2);del xx1[iii]
    except:pass
    return xx1
a,output = addd("AAAGQWERTYUIOPAGCTHJKLAAAGZXCVBNMAGCT".split("AAAG"),"St4rT",""),[]
for i,x in enumerate(a):
    if "AGCT" in x:
        output.append(addd(x.split("AGCT"),"3nD.",""))
    else:output.append(x)
total = []
for i in output:
    if isinstance(i,list):total+=i
    elif isinstance(i,str):total.append(i)
output,typ = [],0
for x,i in enumerate(total):
    if typ == 0 and i == "St4rT":
        try:output.append(total[x+1]);typ = 1
        except:pass
    elif typ == 1 and i == "3nD.":typ = 0
print(output)

['QWERTYUIOP', 'ZXCVBNM']