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窗ShowDialog返回时失败

showdialog wpf c#

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ZombieGoose · 技术社区 · 8 年前

我有一个自定义输入对话框,它请求用户名和在应用程序中执行特定操作的原因。用户点击主窗口上的一个按钮,对话框就会显示出来。

然后用户输入他/她的名字和原因并单击ok。然后对话框关闭,但我(程序)从未收到答案。这是我的输入对话框的XAML:

<Window x:Class="Sequence_Application_2.GUI.ForcedRackInput"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    mc:Ignorable="d"
    Title="Forcera Rack" Height="300" Width="300"
    WindowStartupLocation="CenterScreen">


<Grid>
    <Grid.ColumnDefinitions>
        <ColumnDefinition Width="21*"/>
        <ColumnDefinition Width="274*"/>
    </Grid.ColumnDefinitions>
    <TextBox Name="OperatorNameText"  HorizontalAlignment="Left" Height="23" Margin="15,36,0,0" TextWrapping="Wrap" VerticalAlignment="Top" Width="120" Grid.ColumnSpan="2"/>
    <Label x:Name="label" Content="Namn:" HorizontalAlignment="Left" Margin="10,10,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
    <Label x:Name="label1" Content="Orsak:" HorizontalAlignment="Left" Margin="10,72,0,0" VerticalAlignment="Top" Grid.ColumnSpan="2"/>
    <Border BorderThickness="1" BorderBrush="Black" Grid.ColumnSpan="2" Margin="0,0,0,0.5">
        <TextBox Name="ReasonText" Margin="15,98,15,0" TextWrapping="Wrap" VerticalAlignment="Top" Height="116" />
    </Border>

    <Button Name="OkButton"    IsDefault="True" Content="OK" Click="OkButtonPressed"  HorizontalAlignment="Left" Margin="26.202,233,0,0" VerticalAlignment="Top" Width="75" Cursor="Arrow" Grid.Column="1"/>
    <Button Name="CancelButton" IsCancel="True" Content="Avbryt" Margin="152.202,233,47,0" VerticalAlignment="Top" Cursor="Arrow" Grid.Column="1"/>

</Grid>
</Window>

下面是“隐藏代码”:

namespace Sequence_Application_2.GUI
{
using System.Windows;

public partial class ForcedRackInput : Window
{

    public string OperatorName { get { return OperatorNameText.Text; }  }
    public string ForcedRackReason { get { return ReasonText.Text; } }

    public ForcedRackInput()
    {
        InitializeComponent();
    }

    private void OkButtonPressed(object sender, RoutedEventArgs e)
    {
        this.DialogResult = true;
    }


}
}

public void ForceClosingRack(Flow forcedFlow)
    {
        var forcedRackWindow = new ForcedRackInput();

        string operatorName = "";
        string reasonForForced = "";

        if( forcedRackWindow.ShowDialog() == true)
        {
            operatorName = forcedRackWindow.OperatorName;
            reasonForForced = forcedRackWindow.ForcedRackReason;

        }

    } // code jumps from "if(forcedRackWindow.... to this line when ok is clicked in the dialog

寻找解决方案已经有一段时间了,我正要换工作

1 回复 | 直到 8 年前

1

Krzysztof Bracha 8 年前

我的猜测是问题不在于代码,代码似乎很好,而在于您的 if 陈述

Debug

我猜你是在分配变量 operatorName 和 reasonForForced 但是它们在程序的其他任何地方都没有使用,因此整个 如果 Release 模式

对代码进行一个小的修改,根据变量值嵌入不同的行为,可以证明我的猜测:

private void Button_Click(object sender, RoutedEventArgs e)
{
    var forcedRackWindow = new ForcedWindow();

    string operatorName = "foo";
    string reasonForForced = "foo";

    if (forcedRackWindow.ShowDialog() == true)
    {
        operatorName = forcedRackWindow.OperatorName;
        reasonForForced = forcedRackWindow.ForcedRackReason;
    }

    if(!operatorName.Equals(reasonForForced))
    {
        MessageBox.Show("We are not the same");
    }
}