交换行和列以了解列表

这是我得到的

>>> v = [[x for x in range(4)] for x in range(4)]
>>> h = [[x for x in range(4)] for x in range(4)]
>>> v
[[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]
>>> for i in range(len(v[0])):
>>>    for j in range(len(v[0])):
>>>        h[j][i] = v[i][j]
...        
>>> h
[[0, 0, 0, 0], [1, 1, 1, 1], [2, 2, 2, 2], [3, 3, 3, 3]]

如何用列表理解而不是嵌套的for循环生成h?

更新:

谢谢大家的精彩回答,我很抱歉在我原来的帖子中没有更清楚地表达。我应该初始化 v 像这样:

>>> v = [[randint(0,10) for x in range(4)] for x in range(4)]

例如 V 是:

>>> v
[[5, 1, 0, 5], [8, 9, 9, 10], [3, 7, 1, 1], [6, 6, 10, 7]]
>>> for i in range(len(v[0])):
>>>    for j in range(len(v[0])):
>>>        h[j][i] = v[i][j]
...     
>>> h
[[5, 8, 3, 6], [1, 9, 7, 6], [0, 9, 1, 10], [5, 10, 1, 7]]