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在Python中拆分一个字符串,以便输出有换行符,并且没有“和”括号

string python

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Symphony · 技术社区 · 6 年前

我有一个输入字符串,如下所示:

input_string = [{"name":"Jason","cover":25.1},{"name":"Jake","cover":62.23},{"name":"Amy","cover":70.11}]

我需要输出字符串 line breaks 而且没有 â 和 brackets

output_string_1 = 
name:Jason, cover:25.1
name:Jake, cover:62.23
name:Amy, cover:70.11

最后,我需要输出字符串2,它消除了重复项,并且具有 | 分离器

output_string_2 = 
name | cover
Jason | 25.1
Jake | 62.23
Amy | 70.11

output_string_1 和 output_string_2 应为类型 str

我需要一个解决方案,它可以通过编程实现,而不考虑字符串中元素的数量

3 回复 | 直到 6 年前

Andy Hayden 6 年前

您可以将字符串作为json解析为dict列表:

In [11]: lst = json.loads(input_string)

In [12]: print("name | cover")
     ...: for d in lst:
     ...:     print(d["name"], "|", d["cover"])
     ...:
name | cover
Jason | 25.1
Jake | 62.23
Amy | 70.11

# To return the string
In [13]: "\n".join(["name | cover"] + [d["name"] + " | " + str(d["cover"]) for d in lst])
Out[13]: 'name | cover\nJason | 25.1\nJake | 62.23\nAmy | 70.11'

jpp 6 年前

你可以用 ast.literal_eval 具有 str.join

from ast import literal_eval

L = literal_eval(input_string)

print('\n'.join([f'name:{d["name"]}, cover:{d["cover"]}' for d in L]))

name:Jason, cover:25.1
name:Jake, cover:62.23
name:Amy, cover:70.11

print('\n'.join(['name | cover'] + [f'{d["name"]} | {d["cover"]}' for d in L]))

name | cover
Jason | 25.1
Jake | 62.23
Amy | 70.11

Lukas 6 年前

你可以用你的列表和字典输入你的字符串,你的输出就是真正的dict列表。

>>> import ast
>>> a = ast.literal_eval('[{"name":"Jason","cover":25.1},{"name":"Jake","cover":62.23},{"name":"Amy","cover":70.11}]')
>>> print(a)
[{'name': 'Jason', 'cover': 25.1}, {'name': 'Jake', 'cover': 62.23}, {'name': 'Amy', 'cover': 70.11}]

然后你就可以很容易地。。。

for y in a:
    print("name:" + y["name"] + ", cover:" + str(y["cover"]))

import ast
a = ast.literal_eval('[{"name":"Jason","cover":25.1},{"name":"Jake","cover":62.23},{"name":"Amy","cover":70.11}]')
for y in a:
    # [3 STRINGS]
    print("name:" + y["name"] + ", cover:" + str(y["cover"]))
output_string_1 = "name:" + a[0]["name"] + ", cover:" + str(a[0]["cover"]) + "\nname:"+ a[1]["name"] + ", cover:" + str(a[1]["cover"]) + "\nname:"+ a[2]["name"] + ", cover:" + str(a[2]["cover"]))
output_string_2 = "name | cover\n" + a[0]["name"] + " | " + str(a[0]["cover"]) + "\n"+ a[1]["name"] + " | " + str(a[1]["cover"]) + "\n"+ a[2]["name"] + " | " + str(a[2]["cover"]))
print(output_string_1)
print(output_string_2)

结果是:

[3 STRINGS]
name:Jason, cover:25.1
name:Jake, cover:62.23
name:Amy, cover:70.11

[1 STRING]
name:Jason, cover:25.1
name:Jake, cover:62.23
name:Amy, cover:70.11

[1 STRING]
name | cover
Jason | 25.1
Jake | 62.23
Amy | 70.11

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