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Pythin-tkinter-在某个窗口中放置不同的网格?

grid tkinter python

Martin Kunze · 技术社区 · 3 年前

################################################
#        Left           |         Right        #
#-----------------------|----------------------#
# hello|  hello  |      | hello|  hello | hello#
#-----------------------|------|--------|------#
#                       | hello|               #
################################################

我想生成一些以上类型的tkinter窗口。“左”和“右”是两个按钮。如果我单击左侧,将打开一个新的窗口小部件,其中包含一个应用按钮。如果我点击应用,程序应该记得我用应用按钮打开窗口的哪个按钮,并在左(如果先按左按钮)或右(如果先按下右按钮)下的某个网格中排列单词hello。

我现在的程序是这样的:

################################################
#        Left           |         Right        #
#-----------------------|----------------------#
#       hello           |         hello        #
#-----------------------|----------------------#
#                       |         hello        #
################################################

如何将样式从第二个解决方案更改为第一个解决方案?

我的解决方案二代码:

from tkinter import *

class NewWindow(Toplevel):
    def __init__(self, master = None, apply=None):
        super().__init__(master = master)
        self.title('NewWindow')
        self.master = master
        self.words = 'Hello'

 
        self.bt1 = Button(self, text="apply", command=self.bt_press)
        self.bt1.grid(column=0, row=0)
        self.apply = apply
    def bt_press(self):
        self.apply(self.words)
        self.destroy()

root = Tk()

def new_Editor(key):
    def make_label1(lbl_txt):
        print("root.grid_slaves(0):", root.grid_slaves(column=0))
        row = len(root.grid_slaves(column=0))+1
        lbl = Label(root, text=lbl_txt)
        lbl.grid(row=row, column=0)
    def make_label2(lbl_txt):
        print("root.grid_slaves(1):", root.grid_slaves(column=1))
        row = len(root.grid_slaves(column=1))+1
        lbl = Label(root, text=lbl_txt)
        lbl.grid(row=row, column=1)

    if key == 1:
        a = NewWindow(root, make_label1)
    else:
        a = NewWindow(root, make_label2)

root.title("BasicWindow")

root.basic_bt_l = Button(root, text="Left", command=lambda: new_Editor(1))
root.basic_bt_l.grid(column=0, row=0)


root.basic_bt_r = Button(root, text="Right", command=lambda: new_Editor(2))
root.basic_bt_r.grid(column=1, row=0)

root.mainloop()

0 回复 | 直到 3 年前

acw1668 3 年前

我建议为标签创建两个框架,一个用于左边另一个用于 正确的 。

然后,您可以使用每帧中的标签数量来确定一行和柱要添加的新标签的。

from tkinter import *

class NewWindow(Toplevel):
    def __init__(self, master = None, apply=None):
        super().__init__(master = master)
        self.title('NewWindow')
        self.master = master
        self.words = 'Hello'

        self.bt1 = Button(self, text="apply", command=self.bt_press)
        self.bt1.grid(column=0, row=0)
        self.apply = apply

    def bt_press(self):
        self.apply(self.words)
        self.destroy()

root = Tk()

# adjust the below two settings to suit your requirement
COLS = 3
COLWIDTH = 50

def new_Editor(key):
    def make_label1(lbl_txt):
        # get the children of left frame
        slaves = root.left_frame.grid_slaves()
        print("root.left_frame.grid_slaves():", slaves)
        # determine the row and column of the new label
        row, col = divmod(len(slaves), COLS)
        lbl = Label(root.left_frame, text=lbl_txt)
        lbl.grid(row=row, column=col)

    def make_label2(lbl_txt):
        # get the children of right frame
        slaves = root.right_frame.grid_slaves()
        print("root.right_frame.grid_slaves():", slaves)
        # determine the row and column of the new label
        row, col = divmod(len(slaves), COLS)
        lbl = Label(root.right_frame, text=lbl_txt)
        lbl.grid(row=row, column=col)

    if key == 1:
        a = NewWindow(root, make_label1)
    else:
        a = NewWindow(root, make_label2)

root.title("BasicWindow")
# make the two column same size
root.columnconfigure((0,1), weight=1, uniform=1, minsize=COLS*COLWIDTH)

root.basic_bt_l = Button(root, text="Left", command=lambda: new_Editor(1))
root.basic_bt_l.grid(column=0, row=0)

root.basic_bt_r = Button(root, text="Right", command=lambda: new_Editor(2))
root.basic_bt_r.grid(column=1, row=0)

# frame for left labels
root.left_frame = Frame(root)
root.left_frame.grid(row=1, column=0, sticky='nsew')
# make all the columns inside the frame same size
root.left_frame.columnconfigure(list(range(COLS)), weight=1, uniform=1, minsize=COLWIDTH)

# frame for right labels
root.right_frame = Frame(root)
root.right_frame.grid(row=1, column=1, sticky='nsew')
# make all the columns inside the frame same size
root.right_frame.columnconfigure(list(range(COLS)), weight=1, uniform=1, minsize=COLWIDTH)

root.mainloop()

结果: