我有一个json数组1作为:
[
{ id:0, name:"adam", uName: "aSilver", uId: "123", table: "table1"},
{ id:1, name:"john", uName: "jBerlin", uId: "456", table: "table1"}
]
我还有另一个json数组2:
[
{ id:0, name:"adam", uName: "aSilver, jBerlin", uId: "123, 456", createdBy:
"auto", createdOn: "09/10/2018", desc: "none", table: "table1"},
{ id:1, name:"john", uName: "aSilver, jBerlin", uId: "123, 456", createdBy:
"auto", createdOn: "09/10/2018", desc: "none1", table: "table1"},
{ id:0, name:"steve" uName: "aSilver, jBerlin, pParis", uId: "123, 456,
789", createdBy: "auto", createdOn: "09/10/2018", desc: "none2", table:
"table2"},
{ id:0, name:"nash", uName: "aSilver, jBerlin, pParis", uId: "123, 456,
789", createdBy: "auto", createdOn: "09/10/2018", desc: "none3", table:
"table2"},
{ id:0, name:"sand", uName: "aSilver", uId: "123", createdBy: "auto",
createdOn: "09/10/2018", desc: "none4", table: "table3"}
]
我必须检查array1中uname+uid的组合是否存在于array2中
从array2开始,首先我只能得到唯一的值。唯一值基于“表”键。结果如下:
[
{ id:0, name:"adam", uName: "aSilver, jBerlin", uId: "123, 456", createdBy:
"auto", createdOn: "09/10/2018", desc: "none", table: "table1"},
{ id:0, name:"steve" uName: "aSilver, jBerlin, pParis", uId: "123, 456,
789", createdBy: "auto", createdOn: "09/10/2018", desc: "none2", table:
"table2"},
{ id:0, name:"sand", uName: "aSilver", uId: "123", createdBy: "auto",
createdOn: "09/10/2018", desc: "none4", table: "table3"}
]
现在我可以循环上面的数组,创建新的json数组3,如下所示:
[
{ comparer: "aSilver_123, jBerlin_456", table: "table1" }
{ comparer: "aSilver_456, jBerlin_456, pParis_789", table: "table 2" }
{ comparer: "aSilver_123", table: "table 3" }
]
现在我需要比较数组1&仅限array3比较器键
现在,我发现下面的方法可以检查唯一性,但我必须在对象数组中找到唯一性,这样就行不通了。
Array.prototype.unique = function () {
var r = new Array();
o: for (var i = 0, n = this.length; i < n; i++) {
for (var x = 0, y = r.length; x < y; x++) {
if (r[x] == this[i]) {
return false;
}
}
r[r.length] = this[i];
}
return true;
}
想知道什么是最有效的方法吗?
谢谢
jsfiddle
:
http://jsfiddle.net/50pxjkda/7