考虑报价的字符串拆分

你可以不使用逗号,而是使用 "," :

In [1]: '"a","b","hi, this is Mboyle"'.strip('"').split('","')
Out[1]: ['a', 'b', 'hi, this is Mboyle']

我对这个问题的看法(小心使用!)

s = '"a","b","hi, this is Mboyle"'
new_s = eval(f'[{s}]')
print(new_s)

['a', 'b', 'hi, this is Mboyle']

编辑(更安全的版本):

import ast.literal_eval
s = '"a","b","hi, this is Mboyle"'
new_s = ast.literal_eval(f'[{s}]')

解决了的。

with gzip.open(file, 'rt') as handler:
    for row in csv.reader(handler, delimiter=","):

你可以在分割中包括报价,所以 .split('","')

你可以用 re.split :

import re
s = '"a","b","hi, this is Mboyle"'
new_s = list(map(lambda x:x[1:-1], re.split('(?<="),(?=")', s)))

输出:

['a', 'b', 'hi, this is Mboyle']

然而, re.findall

new_result = re.findall('"(.*?)"', s)

输出:

['a','b','嗨,我是姆博伊尔']