如何在python中获得对xmpp客户机的响应

我必须注册一个处理程序和进程:

def messageCB(sess,mess):
    print 'MESSAGE'*100
    nick=mess.getFrom().getResource()
    text=mess.getBody()
    #print mess,nick
    print text

client.RegisterHandler('message',messageCB)

while 1:
    client.Process(1)

好帖子。我注意到这个代码片段也在xmppy sourceforge网站的logger示例中。

I wonder if it is possible to reply to incoming messages. The code above only receives and the nickname resource ID does not indicate who the sender is (in terms of JID format, user@server) unless xmpppy can translate that appropriately. So how might one take the received message nd "echo" it back to the sender? Or is that not easily possible with the xmpppy library and need to find a different XMPP library?