我正在尝试用Javascript制作一个简单的渐变效果。
当我在我的文本编辑器+谷歌Chrome中尝试它时,它不起作用,所以我将它复制到JSFiddle中,它起了作用!
http://jsfiddle.net/yLFFt/
然而,我无法弄清楚JSFiddle中的哪些内容是正确的,而在我的原始副本中是不正确的。
我将在Notepad++中发布代码:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<html>
<head>
<title>My Site</title>
<link rel="stylesheet" type="text/css" href="style2.css">
</style>
<script>
(function(i,s,o,g,r,a,m){i['GoogleAnalyticsObject']=r;i[r]=i[r]||function(){
(i[r].q=i[r].q||[]).push(arguments)},i[r].l=1*new Date();a=s.createElement(o),
m=s.getElementsByTagName(o)[0];a.async=1;a.src=g;m.parentNode.insertBefore(a,m)
})(window,document,'script','//www.google-analytics.com/analytics.js','ga');
ga('create', 'UA-08000000-1', 'mysite.com');
ga('send', 'pageview');
</script>
<script type="text/javascript" src="js/jquery_1.4.2.js"></script>
<script type="text/javascript" src="js/flashing_logos.js"></script>
</head>
<body>
<div id="background_logo">
<img src="http://drivesmartbc.ca/sites/default/files/images/smiley%20face.thumbnail.jpg">
</div>
<div id="logo">
<img src="https://lh4.googleusercontent.com/-b86bjfIcDMk/TXpUmwBK_FI/AAAAAAAAARY/ws-ypr2P39I/s200/9+smiley+face.jpg">
</div>
<div id="signup">
<p id="instruction"> Get on board! </br> Enter your email to receive updates:</p>
<script type="text/javascript" src="js/form-validation.js"></script>
<form id="emailForm" action='#' method="post">
<input name="email" id="email" type="text" />
<input type="button" value="Submit" name="submit" id="submit" />
</form>
<p id="success" class="success">Thanks - we'll keep in touch!</p>
<p id="error" class="warning">There was an error</p>
</div>
</body>
</html>
我的Javascript看起来像这样:
function fade(element) {
var op = 1; // initial opacity
var timer = setInterval(function () {
if (op <= 0.1){
clearInterval(timer);
element.style.display = 'none';
}
element.style.opacity = op;
element.style.filter = 'alpha(opacity=' + op * 100 + ")";
op -= op * 0.1;
}, 50);
}
fade(document.getElementById('background_logo'));
