代码之家 › 专栏 › 技术社区 › Samir Tendulkar

在python split函数上运行forloop时出错

python-3.x

-3

Samir Tendulkar · 技术社区 · 7 年前

我有一个下面的代码,用户可以添加一个英文文本数字由一个字母分隔 ,

输入示例: 叁亿叁仟伍佰陆拾伍佰壹拾叁

输出应为:

下面是我的代码

print("Please type your number below")
value = input("")
string = ""
for unit_value in value.split(", "):
    string = str(challenge1(unit_value.lower()))   #function challenge1 code below (In my code it comes before )
    print(string)

我的输出如下 为什么代码在第一个循环之后没有运行

335             #I can switch the order no matter what number I put 1st it shows
None            #The 2nd and 3rd loop always show none no matter what the number 
None

我添加了打印报表,看看是否一切都很好

print("Please type your number below")
value = input("")
string = ""
for unit_value in value.split(", "):
    print(unit_value)   #extra print added to see unit_value
    string = str(challenge1(unit_value.lower()))
    print(unit_value)

output is correct as below 

three hundred thirty five
six million five hundred one
three

下面是函数challenge1的详细信息

def challenge1(single_word, complete_number={}):
    if not complete_number:
        uniques = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve",
                   "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]


        teners = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]

        big_nums = ["hundred", "thousand", "million"]    


        for index, word in enumerate(uniques):
            complete_number[word] = (1, index)
        for index, word in enumerate(teners):
            complete_number[word] = (1, index * 10)
        for index, word in enumerate(big_nums):
            complete_number[word] = (10 ** (index * 3 or 2), 0)


        current = 0
        result = 0

        for word in single_word.split():

            if word not in complete_number:
                print("Input is not a number. Please see the examples of how to enter number /n six  /n negative seven"
                      " hundred twenty nine, /n one million one hundred one")


            scale, increment = complete_number[word]
            current = current * scale + increment
            if scale > 100:
                result += current
                current = 0
     return result + current

1 回复 | 直到 7 年前

Jay Shankar Gupta 7 年前

编辑你的函数你需要清除()你的字典,因为它是静态声明。您声明的字典是静态的,它不会在每次调用时重新创建,因此您需要清除它或按以下方式编写:

def challenge1(single_word): 
   complete_number={}

更正代码:

def challenge1(single_word, complete_number={}):
    if not complete_number:
        uniques = ["zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve",
                   "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]


        teners = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"]

        big_nums = ["hundred", "thousand", "million"]

        negative = ["negative"]    

        for index, word in enumerate(uniques):
            complete_number[word] = (1, index)
        for index, word in enumerate(teners):
            complete_number[word] = (1, index * 10)
        for index, word in enumerate(big_nums):
            complete_number[word] = (10 ** (index * 3 or 2), 0)


        current = 0
        result = 0

        for word in single_word.split():

            if word not in complete_number:
                print("Input is not a number. Please see the examples of how to enter number /n six  /n negative seven"
                      " hundred twenty nine, /n one million one hundred one")


            scale, increment = complete_number[word]
            current = current * scale + increment
            if scale > 100:
                result += current
                current = 0
        complete_number.clear()
        return result + current