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如何在R中查找数据表的两个多类别列之间的差异/setdiff()

set-difference data.table datatable group-by r

0

Shubham · 技术社区 · 3 年前

我有两个数据表中的数据,如下所示 (比此处显示的列多得多) -

数据表1 =data\u销售

站点Id	国	产品ID
1000375476	加拿大	UG10000-WISD
1000375476	加拿大	UGD12895
1000706152	瑞士	UG10000-WISD
1000706152	瑞士	UG80000-NTCD-G
1000797366	意大利	UG10000-WISD
1000797366	意大利	UG12210

数据表2 =data\u许可证

站点Id	国	产品ID
1000375476	加拿大	UG10000-WISD
1000375476	加拿大	UGD12895
1000797366	意大利	UG12785
1000797366	意大利	UG12210

我想计算data\u sale中所有站点ID的唯一产品ID的设置差异,保留所有行。

这是我到目前为止所做的-

对于这两个数据表,我创建了一个包含所有独特产品的新列。

data_sale <-
  data_sale[, `unique_products` := paste0(unique(`Product ID`), collapse = ","), 
              keyby = c("Site Id")]

data_licenses <-
  data_licenses[, .(`unique_products` = paste0(unique(`Product ID`), collapse = ",")), 
              keyby = c("Site Id")]

左侧合并了data\u销售和data\u许可证

merge(data_sale, data_licenses, by = 'Site Id', all.x = TRUE)

现在合并的数据表如下所示-

站点Id	国	产品ID	独特的产品。data\u销售	独特的产品。data\u许可证
1000375476	加拿大	UG10000-WISD	UG10000-WISD,UGD12895	UG10000-WISD,UGD12895
1000375476	加拿大	UGD12895	UG10000-WISD,UGD12895	UG10000-WISD,UGD12895
1000706152	瑞士	UG10000-WISD	UG10000-WISD,UG80000-NTCD-G	不适用
1000706152	瑞士	UG80000-NTCD-G	UG10000-WISD,UG80000-NTCD-G	不适用
1000797366	意大利	UG10000-WISD	UG10000-WISD,UG12210	UG12785、UG12210
1000797366	意大利	UG12210	UG10000-WISD,UG12210	UG12785、UG12210

问题是在我的最后一步中,我希望有一个新的列显示data\u sale和data\u许可证产品之间的差异,它应该如下所示-

站点Id	国	产品ID	独特的产品。data\u销售	独特的产品。data\u许可证	差别
1000375476	加拿大	UG10000-WISD	UG10000-WISD,UGD12895	UG10000-WISD,UGD12895	不适用
1000375476	加拿大	UGD12895	UG10000-WISD,UGD12895	UG10000-WISD,UGD12895	不适用
1000706152	瑞士	UG10000-WISD	UG10000-WISD,UG80000-NTCD-G	不适用	UG10000-WISD,UG80000-NTCD-G
1000706152	瑞士	UG80000-NTCD-G	UG10000-WISD,UG80000-NTCD-G	不适用	UG10000-WISD,UG80000-NTCD-G
1000797366	意大利	UG10000-WISD	UG10000-WISD,UG12210	UG12785、UG12210	UG10000-WISD
1000797366	意大利	UG12210	UG10000-WISD,UG12210	UG12785、UG12210	UG10000-WISD

任何关于如何实现这一目标的线索都将大有裨益。谢谢

下面是使用dput()对合并数据表进行处理的数据

structure(list(`Site Id` = c("1000375476", "1000375476", "1000706152", 
"1000706152", "1000797366", "1000797366"), Country = c("Canada", 
"Canada", "Switzerland", "Switzerland", "Italy", "Italy"), `Product ID` = c("UG10000-WISD", 
"UGD12895", "UG10000-WISD", "UG80000-NTCD-G", "UG10000-WISD", 
"UG12210"), unique_products.x = c("UG10000-WISD,UGD12895", "UG10000-WISD,UGD12895", 
"UG10000-WISD,UG80000-NTCD-G", "UG10000-WISD,UG80000-NTCD-G", 
"UG10000-WISD,UG12210", "UG10000-WISD,UG12210"), unique_products.y = c("UG10000-WISD,UGD12895", 
"UG10000-WISD,UGD12895", NA, NA, "UG12785,UG12210", "UG12785,UG12210"
)), sorted = "Site Id", class = c("data.table", "data.frame"), row.names = c(NA, 
-6L), .internal.selfref = <pointer: 0x556bb5c10a40>)

0 回复 | 直到 3 年前

1

0

jblood94 3 年前

这将使产品进入 data_sale 不在 data_license 通过 Site Id 。与串联唯一的产品ID不同,使用唯一列作为字符向量更容易。

library(data.table)

data_licenses <- data.table(`Site Id` = c("1000375476", "1000375476", "1000797366", "1000797366"),
                            Country = c("Canada", "Canada", "Italy", "Italy"),
                            `Product ID` = c("UG10000-WISD", "UGD12895", "UG12785", "UG12210"))
data_sale <- data.table(`Site Id` = c("1000375476", "1000375476", "1000706152", "1000706152", "1000797366", "1000797366"),
                        Country = c("Canada", "Canada", "Switzerland", "Switzerland", "Italy", "Italy"),
                        `Product ID` = c("UG10000-WISD", "UGD12895", "UG10000-WISD", "UG80000-NTCD-G", "UG10000-WISD", "UG12210"))

data_unique <- data_sale[
  , .(unique_products.data_sale = .(unique(`Product ID`))), c("Site Id", "Country")
][
  data_licenses[, .(unique_products = .(unique(`Product ID`))), "Site Id"],
  unique_products.data_licenses := i.unique_products,
  on = "Site Id"
][
  , difference := lapply(.I, function(i) setdiff(unique_products.data_sale[[i]], unique_products.data_licenses[[i]]))
]
print(data_unique)
#>       Site Id     Country   unique_products.data_sale unique_products.data_licenses                  difference
#> 1: 1000375476      Canada       UG10000-WISD,UGD12895         UG10000-WISD,UGD12895                            
#> 2: 1000706152 Switzerland UG10000-WISD,UG80000-NTCD-G                               UG10000-WISD,UG80000-NTCD-G
#> 3: 1000797366       Italy        UG10000-WISD,UG12210               UG12785,UG12210                UG10000-WISD

2

0

RobertoT 3 年前

可能有一种方法可以尝试组合一些内置函数,但有一个简单自定义函数的示例:

find_differences = function(x,y){
  # x: column list of strings we want to compare to
  # y: other column list
  x = strsplit(x,',') # transform strings to lists
  y = strsplit(y,',')
  
  differences = list()

  for(i in seq(1,length(x))){  # for every row (nested-list)
    
    if(identical(x[[i]],y[[i]])){
      row_diff = NA
    }
    else{
    row_diff = paste(x[[i]][ ! x[[i]] %in% y[[i]] ],collapse=',')
    }
    
    differences = c(differences,row_diff)
  }
  return(differences)
}

以您的例子:

example = rename(example, 
                 unique_products.data_sale = unique_products.x,
                 unique_products.data_licenses = unique_products.y)

example$difference = find_differences(example$unique_products.data_sale, example$unique_products.data_license)

> example
      Site Id     Country     Product ID   unique_products.data_sale unique_products.data_licenses                  difference
1: 1000375476      Canada   UG10000-WISD       UG10000-WISD,UGD12895         UG10000-WISD,UGD12895                          NA
2: 1000375476      Canada       UGD12895       UG10000-WISD,UGD12895         UG10000-WISD,UGD12895                          NA
3: 1000706152 Switzerland   UG10000-WISD UG10000-WISD,UG80000-NTCD-G                          <NA> UG10000-WISD,UG80000-NTCD-G
4: 1000706152 Switzerland UG80000-NTCD-G UG10000-WISD,UG80000-NTCD-G                          <NA> UG10000-WISD,UG80000-NTCD-G
5: 1000797366       Italy   UG10000-WISD        UG10000-WISD,UG12210               UG12785,UG12210                UG10000-WISD
6: 1000797366       Italy        UG12210        UG10000-WISD,UG12210               UG12785,UG12210                UG10000-WISD

3

0

langtang 3 年前

如何快速获得每个站点的差异;然后可以将结果合并回具有 Site Id :

data_licenses[, .(licen_p = .(.(`Product ID`))), by = `Site Id`] %>% 
  .[data_sale[, .(sale_p= .(.(`Product ID`))), by=`Site Id`],on=.(`Site Id`)] %>% 
  .[,.(difference = toString(unlist(setdiff(sale_p, licen_p)))), by=`Site Id`]

输出:

      Site Id                   difference
1: 1000375476                             
2: 1000706152 UG10000-WISD, UG80000-NTCD-G
3: 1000797366        UG10000-WISD, UG12210