我有一个程序,它将2个2的补码二进制数相加并输出。它们是从文件中读取的,第一个二进制数是2的补码。第二个二进制数是有偏差的符号。为了改变形式偏向于2的补码,我们翻转最左边的一位。然后,我们将两个二进制数相加,并将输出输出到文件。我遇到的问题是理解输出。这是输出,其中第一个二进制数是2的补码,第二个是有偏差的符号。
01000000 <- 2's complement 64
+ 11000000 <- biased notation 64
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10000000 <- 2's complement Overflow
01111111 <- 2's complement 127
+ 00000000 <- biased notation -128
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11111111 <- 2's complement -1
00000011 <- 2's complement 3
+ 10000111 <- biased notation 7
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00000110 <- 2's complement 6
00001111 <- 2's complement 15
+ 10000111 <- biased notation 7
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00010010 <- 2's complement 18
10000000 <- 2's complement -128
+ 11111111 <- biased notation 127
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11111111 <- 2's complement -1
11110000 <- 2's complement -16
+ 10001000 <- biased notation 8
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11111000 <- 2's complement -8
10000001 <- 2's complement -127
+ 00000001 <- biased notation -127
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00000010 <- 2's complement Underflow
01111111 <- 2's complement 127
+ 00000000 <- biased notation -128
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11111111 <- 2's complement -1
01110101 <- 2's complement 117
+ 11010001 <- biased notation 81
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01000110 <- 2's complement 70
00000000 <- 2's complement 0
+ 10000000 <- biased notation 0
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00000000 <- 2's complement 0
00001111 <- 2's complement 15
+ 11110000 <- biased notation 112
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01111111 <- 2's complement 127
00001111 <- 2's complement 15
+ 10000001 <- biased notation 1
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00010000 <- 2's complement 16
00000111 <- 2's complement 7
+ 11110000 <- biased notation 112
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01110111 <- 2's complement 119
11111111 <- 2's complement -1
+ 01111111 <- biased notation -1
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10101010 <- 2's complement -86
00000000 <- 2's complement 0
+ 10000000 <- biased notation 0
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00000000 <- 2's complement 0
11111111 <- 2's complement -1
+ 11111111 <- biased notation 127
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00101010 <- 2's complement 42
给定第三个例子,3+7=6。
这是正确的吗?这似乎不正确,但其他例子是正确的。比如-16+8=-8。
所以我的问题是…这个文件的输出正确吗?
