使用grep仅打印整行中的图案

类似于 grep -oE '<[^>]+>' :

$ echo "Job <472971> Job Name <aaaaaaaaaaa> User <bbbbbbbbb> Project <cccccc> Status <RUN> Queue <AL_Ptime>Interactive pseudo-terminal shell mode Submitted from host <lsf_login07> CWD </asdfghjklll/dsadasd/asda>" \
| grep -oE '<[^>]+>'
<472971>
<aaaaaaaaaaa>
<bbbbbbbbb>
<cccccc>
<RUN>
<AL_Ptime>
<lsf_login07>
</asdfghjklll/dsadasd/asda>

如果您想去掉换行符并在换行符之间留有空格,可以通过管道将其转换为一个简单的 awk公司 这样地:

grep -oE '<[^>]+>' |  awk '{printf "%s%s", (NR==1?"":" "), $0}'

或与 tr公司

grep -oE '<[^>]+>' | tr "\n" " "

假设OP使用一个包含许多这样的行的输入文件,可以使用GNU awk公司 :

$ cat tst.awk
BEGIN { FPAT="<[^>]+>" }
{ for (i=1; i<=NF; i++) printf "%s%s", (i==1?"":" "), $i
  printf "\n"
}

使用它:

awk -f tst.awk file

其中文件是:

$ cat file
Job <472971> Job Name <aaaaaaaaaaa> User <bbbbbbbbb> Project <cccccc> Status <RUN> Queue <AL_Ptime>Interactive pseudo-terminal shell mode Submitted from host <lsf_login07> CWD </asdfghjklll/dsadasd/asda>
Job <472971> Job Name <aaaaaaaaaaa> User <bbbbbbbbb> Project <cccccc> Status <RUN> Queue <AL_Ptime>Interactive pseudo-terminal shell mode Submitted from host <lsf_login07> CWD </asdfghjklll/dsadasd/asda>

$ awk 'BEGIN{FPAT="<[^>]+>"} \
        {for (i=1; i<=NF; i++) printf "%s%s", (i==1?"":" "), $i; printf "\n"}' file
<472971> <aaaaaaaaaaa> <bbbbbbbbb> <cccccc> <RUN> <AL_Ptime> <lsf_login07> </asdfghjklll/dsadasd/asda>
<472971> <aaaaaaaaaaa> <bbbbbbbbb> <cccccc> <RUN> <AL_Ptime> <lsf_login07> </asdfghjklll/dsadasd/asda>