我要我的算法做什么

我想有一堆随机的词作为我的人口中的个体,谁的健康被比作一个“最佳”的词。如果单词的长度相等,则表示适合+1。对于每个相同的字符,它的适应度也是+1,如果它在同一索引中,则是+1.1。

不幸的是,我有一个真正的时间了解主任文件。这是我到目前为止所做的尝试。

尝试的代码

from deap import creator
from deap import tools
import random
import time
from create_random_string import get_random_word

ans = "hot"
creator.create("FitnessMax", base.Fitness, weights=(len(ans)+2,))
creator.create("Individual", str, fitness=creator.FitnessMax)

toolbox = base.Toolbox()
toolbox.register("individual",tools.initRepeat,creator.Individual,get_random_word, n=1)
toolbox.register("population", tools.initRepeat, list, toolbox.individual)

def evalOneMax(individual):
    fitness = 0
    if(len(ans)==len(individual)):
        fitness+=1
        for i in range(0,len(ans)):
            if(ans[i]==individual[i]):
                fitness+=1.1

    for i in range(0,len(ans)):
       if individual.find(ans[i]) != -1:
           fitness+=1

    return (fitness,)

#----------
# Operator registration
#----------
# register the goal / fitness function
toolbox.register("evaluate", evalOneMax)

# register the crossover operator
toolbox.register("mate", tools.cxTwoPoint)

# register a mutation operator with a probability to
# flip each attribute/gene of 0.05
toolbox.register("mutate", tools.mutFlipBit, indpb=0.05)

# operator for selecting individuals for breeding the next
# generation: each individual of the current generation
# is replaced by the 'fittest' (best) of three individuals
# drawn randomly from the current generation.
toolbox.register("select", tools.selTournament, tournsize=3)

#----------

if __name__== '__main__':
    random.seed(64)

    pop = toolbox.population(n=50)

    # CXPB  is the probability with which two individuals
    #       are crossed
    #
    # MUTPB is the probability for mutating an individual
    CXPB, MUTPB = 0.5, 0.2

    print("Start of evolution")
    fitnesses = list(map(toolbox.evaluate, pop))

    for ind, fit in zip(pop, fitnesses):
        ind.fitness.values = fit

代码解释(据我所知)

替代方案

我尝试了另一种方法,将单词作为变量保存在单独的类中,就像这样,但是这对于我正在使用的其他deaps函数来说确实不太好。用这种方法,我得到了deap给出的交叉算子的误差。我宁愿不必创建自己的交叉运算符。

creator.create("FitnessMax", base.Fitness, weights=(len(ans),))
creator.create("Individual", str, fitness=creator.FitnessMax, word=get_random_word(True,0))

toolbox = base.Toolbox()
toolbox.register("individual",creator.Individual)
toolbox.register("population", tools.initRepeat, list, toolbox.individual)

编辑

更具体地说,如果我在evalOneMax中放一个“print(individual)”行 功能it输出

<generator object initRepeat.<locals>.<genexpr> at 0x1076ffe60>

如何访问映射的随机词以及个人的适合性