在C语言中从二进制文件读写整数++

尝试编写一个简单的程序,将整数值写入文件,然后按写入顺序读取和显示整数。写入文件的整数为{0,2,….18}。代码如下:

// Example program
#include <iostream>
#include <string>
#include <sstream>
#include <stdlib.h>
#include <stdio.h>
#include <fstream>
using namespace std;

int main()
{
    typedef unsigned int uint32_t;
    // Write to file
    std::ofstream osObj;
    string filename = "testFile";
    osObj.open(filename.c_str(), std::ofstream::binary);

    for (uint32_t i=0; i<10; ++i)
    {
        uint32_t a = i*2;
        osObj.write(reinterpret_cast<const char *>(&a), sizeof(a));
        //osObj.write((char *)(&a), sizeof(a));
    }

    //read from file
    std::ifstream isObj;
    isObj.open(filename.c_str(), std::ofstream::binary);
    if (isObj.fail()) { cout<<"Failed to open file"<<endl; }

    for (uint32_t i=0; i<10; ++i)
    {
        char val[sizeof(uint32_t)];
        isObj.read(val, sizeof(val));
        uint32_t* valUint = reinterpret_cast<uint32_t *>(val);
        cout<<*(valUint)<<endl;
    }
    return 0;
}

这并没有产生预期的结果。我得到以下输出:

62586880
62586880
62586880
62586880
62586880
62586880
62586880
62586880
62586880
62586880

字节顺序为小端。我错过了什么?