将MacOS.app文件注册为打开文件扩展名时的默认文件,将文件作为参数单击

我有一个名为FileOpener.app的应用程序,它有以下内容:

FileOpener.app
  - Contents
    Info.plist
    - MacOS
      - FileOpener
    - Resources

Info.plist的内容如下:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
    <key>CFBundleDevelopmentRegion</key>
    <string>English</string>
    <key>CFBundleExecutable</key>
    <string>FileOpener</string>
    <key>CFBundleIdentifier</key>
    <string>com.example.FileOpener</string>
    <key>CFBundleInfoDictionaryVersion</key>
    <string>6.0</string>
    <key>CFBundleName</key>
    <string>FileOpener</string>
    <key>CFBundlePackageType</key>
    <string>APPL</string>
    <key>CFBundleShortVersionString</key>
    <string>1.0</string>
    <key>CFBundleVersion</key>
    <string>1.0</string>

    <!-- Document Types -->
    <key>CFBundleDocumentTypes</key>
    <array>
        <dict>
            <key>CFBundleTypeName</key>
            <string>Test File</string>
            <key>CFBundleTypeRole</key>
            <string>Editor</string>
            <key>LSHandlerRank</key>
            <string>Owner</string>
            <key>LSItemContentTypes</key>
            <array>
                <string>com.example.testfile</string>
            </array>
        </dict>
    </array>

    <key>UTExportedTypeDeclarations</key>
    <array>
        <dict>
            <key>UTTypeIdentifier</key>
            <string>com.example.testfile</string>
            <key>UTTypeDescription</key>
            <string>Test File</string>
            <key>UTTypeConformsTo</key>
            <array>
                <string>public.data</string>
            </array>
            <key>UTTypeTagSpecification</key>
            <dict>
                <key>public.filename-extension</key>
                <array>
                    <string>testfile</string>
                </array>
                <key>public.mime-type</key>
                <string>application/x-testfile</string>
            </dict>
        </dict>
    </array>


    <key>NSDocumentsFolderUsageDescription</key>
    <string>Description goes here</string>

    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>file</string>
    </array>
</dict>
</plist>

我有一些超级简单的生锈代码:

fn log_message(message: &str) {
    let mut log_file = OpenOptions::new()
        .create(true)
        .append(true)
        .open("/tmp/fileopener.log")
        .unwrap();
    writeln!(log_file, "{}", message).unwrap();
}

fn main() -> notify::Result<()> {
    let args: Vec<String> = env::args().collect();
    log_message(&format!("Received arguments: {:?}", args));

    if args.len() != 2 {
        eprintln!("Usage: {} <path to .testfile file>", args[0]);
        log_message("Incorrect number of arguments.");
        return Ok(());
    }
}

因此,每当调用二进制文件时,它都会将参数记录到tmp文件中,期望将文件路径的辅助参数传递给它。

如果我跑/FileOpener/Contents/MacOS/FileOpener/path/to/file.testfile

参数传递正确。

如果我尝试将file.testfile拖动到FileOpener.app上,则file.testfile的路径不会作为参数传递,唯一的参数是FileOpener.app的路径。如果我尝试双击file.testfile,FileOpener.app确实会打开,但file.testfile的路径不会作为arg传递,只有arg是FileOpener.app的路径。

我想做的是注册.testfile扩展名,这样当双击时,它会打开FileOpener.app,并将点击(或拖动)的文件的路径作为第二个参数传递。

我也尝试过代码签名, sudo codesign --deep --force --sign - ./FileOpener.app ,将其复制到/Applications中,通过安全性启用全磁盘访问等。我需要的辅助参数,即单击的文件的路径,永远不会传入。