在Python中选择一系列列而不使用numpy

你太复杂了。用你的手指划过一行 a[k:] ,然后用 row[k+1]

>>> [row[k+1] for row in a[k:]]
[2, 7]

a = [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]]
k = 0
print(list(list(zip(*a[k:]))[k+1])) # [2, 7]

这就是你要找的吗?

cols = [1,2,3] # extract middle 3 columns
cols123 = [[l[col] for col in cols] for l in a]
# [[2, 3, 4], [7, 8, 9]]