代码之家 › 专栏 › 技术社区 › hifi01

preg\u match\u all:更改字符串$match

preg-match-all php

1

hifi01 · 技术社区 · 9 年前

到目前为止:我正在做一个preg\u match\u all搜索,我的输出是:Donald,Daisy,Huey,Dewey和Louie

$duckburg = array();
preg_match_all($pattern,$subject,$match);
$duckburg['residents'] = $match[1];
print_r($duckburg['residents']);

输出:

Array ( [residents] => Array ( [0] => Donald [1] => Daisy [2] => Huey [3] => Dewey [4] => Louie )

我的问题是:我想在每个字符串中添加“Duck”

$lastname = " Duck"

输出应为:

Array ( [residents] => Array ( [0] => Donald Duck [1] => Daisy Duck [2] => Huey Duck [3] => Dewey Duck [4] => Louie Duck )

我试过(但不起作用):

preg_match_all($pattern,$subject,$match);
$matchy = $match.$lastname;
$duckburg['residents'] = $matchy[1];
print_r($duckburg['residents']);

2 回复 | 直到 9 年前

1

0

Toto 9 年前

Array_map

$match = Array ( 'residents' => Array ('Donald','Daisy','Huey','Dewey','Louie'));
$duckburg['residents'] = array_map(function($n) { return "$n Duck"; }, $match['residents']);
var_dump($duckburg);

array(1) {
  ["residents"]=>
  array(5) {
    [0]=>
    string(11) "Donald Duck"
    [1]=>
    string(10) "Daisy Duck"
    [2]=>
    string(9) "Huey Duck"
    [3]=>
    string(10) "Dewey Duck"
    [4]=>
    string(10) "Louie Duck"
  }
}

2

0

Cagy79 9 年前

迭代数组是一种可能的选择:

$lastname = " Duck";
preg_match_all($pattern,$subject,$matches);
foreach($matches as $key => $val){
    $duckburg['residents'][$key] = $val . $lastname;
}
print_r($duckburg['residents']);