鼠标“点击”时的Pygame操作。rect?

我一直在编写一个测试函数,以了解鼠标在pygame.rect上的“点击”操作将如何产生响应。

到目前为止:

def test():
    pygame.init()
    screen = pygame.display.set_mode((770,430))
    pygame.mouse.set_visible(1)
    background = pygame.Surface(screen.get_size())
    background = background.convert()
    background.fill((250,250,250))
    screen.blit(background, (0,0))
    pygame.display.flip()

    ## set-up screen in these lines above ##

    button = pygame.image.load('Pictures/cards/stand.png').convert_alpha()
    screen.blit(button,(300,200))
    pygame.display.flip()

    ## does button need to be 'pygame.sprite.Sprite for this? ##
    ## I use 'get_rect() ##
    button = button.get_rect()

    ## loop to check for mouse action and its position ##
    while True:
        for event in pygame.event.get():
            if event.type == pygame.mouse.get_pressed():
                ## if mouse is pressed get position of cursor ##
                pos = pygame.mouse.get_pos()
                ## check if cursor is on button ##
                if button.collidepoint(pos):
                    ## exit ##
                    return

我在谷歌上看到过一些页面,人们正在使用或建议使用 pygame.sprite.Sprite 我想这就是我的问题所在。我已经检查了pygames文档,方法之间没有太多的衔接,imho。我显然错过了一些简单的事情,但是,我想 get_rect 会让pygames中的图像在按下时能够检查鼠标位置是否在其上方吗?

编辑: 我想我需要打电话给 pygame.sprite.sprite游戏 如何使图像/矩形交互?