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两个装饰工产生冲突

webargs authlib flask-restful python-decorators python

-1

Denis Steinman · 技术社区 · 6 年前

我需要同时使用两个装饰器,但它们相互冲突。这是我的路线:

channel_args = {
    'name': fields.Str(required=True),
    'description': fields.Str(required=False, missing=None, default=None)
}
class ChannelListRoutes(Resource):

    @require_oauth
    @use_args(channel_args, locations=['json'])
    def post(self, args):
        channel = Channel()
        channel.name = args['name']
        channel.description = args['description']
        channel.user_id = current_token.user.id
        db.session.commit()
        db.session.flush()
        return ChannelJson(channel).to_json(), status.HTTP_201_CREATED

哪里 require_oauth = ResourceProtector() 从 作者库 , @use_args 使用 网络参数 图书馆。
我通过发送数据卷曲 :

curl -H "Authorization: Bearer {access_token}" -H "Content-Type: application/json" -X POST -d "{\"name\":\"Pets\"}" http://127.0.0.1:5000/api/channels

请求后,我的应用程序刚刚崩溃:

Traceback (most recent call last):
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 2309, in __call__
    return self.wsgi_app(environ, start_response)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 2295, in wsgi_app
    response = self.handle_exception(e)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask_restful/__init__.py", line 273, in error_router
    return original_handler(e)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 1741, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/_compat.py", line 34, in reraise
    raise value.with_traceback(tb)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 2292, in wsgi_app
    response = self.full_dispatch_request()
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 1815, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask_restful/__init__.py", line 273, in error_router
    return original_handler(e)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 1718, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/_compat.py", line 34, in reraise
    raise value.with_traceback(tb)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 1813, in full_dispatch_request
    rv = self.dispatch_request()
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask/app.py", line 1799, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask_restful/__init__.py", line 484, in wrapper
    return self.make_response(data, code, headers=headers)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask_restful/__init__.py", line 513, in make_response
    resp = self.representations[mediatype](data, *args, **kwargs)
  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/flask_restful/representations/json.py", line 21, in output_json
    dumped = dumps(data, **settings) + "\n"
  File "/usr/lib/python3.6/json/__init__.py", line 238, in dumps
    **kw).encode(obj)
  File "/usr/lib/python3.6/json/encoder.py", line 201, in encode
    chunks = list(chunks)
  File "/usr/lib/python3.6/json/encoder.py", line 437, in _iterencode
    o = _default(o)
  File "/usr/lib/python3.6/json/encoder.py", line 180, in default
    o.__class__.__name__)
TypeError: Object of type 'function' is not JSON serializable

附笔。 我试图更改decorators的顺序,但也没有帮助,尽管它生成了一个新的堆栈跟踪:

  File "/home/ghostman/Projects/vistory/auth/venv/lib/python3.6/site-packages/webargs/core.py", line 482, in wrapper
    return func(*new_args, **kwargs)
TypeError: wrapper() takes 1 positional argument but 2 were given

1 回复 | 直到 6 年前

1

bruno desthuilliers 6 年前

reading the doc might help.. . require_oauth 需要一个“scope”参数,因此正确的语法是

@require_oauth(scope)
@use_args(channel_args, locations=['json'])
def post(self, args):
    # ...

也可以通过传递 None 明确地( @require_oauth(None) )或含蓄地通过调用 需要 没有任何争论,但是你仍然需要打电话给装修工:

@require_oauth()
@use_args(channel_args, locations=['json'])
def post(self, args):
    # ...

=>注意parens(python中的call运算符)。