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使用GROUP BY进行Oracle SQL查询以汇总统计信息

pivot group-by oracle sql

sernaferna · 技术社区 · 17 年前

ID   BATCH   STATUS
1    1       0
2    1       0
3    1       1
4    2       0

是主键,每个“批次”都有多行,每行都有一个状态代码

我需要写一个查询来总结

BATCH  STATUS0  STATUS1  STATUS2
1      2        1        0
2      1        0        0

状态

状态
状态

SELECT batch, COUNT(status)
FROM table
WHERE status = 0
GROUP BY batch

状态有一列

4 回复 | 直到 17 年前

Tony Andrews 17 年前

select batch 
,      count(case when status=1 then 1 end) status1
,      count(case when status=2 then 1 end) status2
,      count(case when status=3 then 1 end) status3
from   table
group by batch;

on my blog .

使用DECODE的版本(特定于Oracle,但不太冗长):

select batch 
,      count(decode(status,1,1)) status1
,      count(decode(status,2,1)) status2
,      count(decode(status,3,1)) status3
from   table
group by batch;

tekBlues 17 年前

select batch,
sum(select case when status = 0 then 1 else 0 end) status0,
sum(select case when status = 1 then 1 else 0 end) status1,
sum(select case when status = 2 then 1 else 0 end) status2
from table
group by batch

diederikh 17 年前

select batch,
sum((decode(status,0,1,0)) status0,
sum((decode(status,1,1,0)) status1,
sum((decode(status,2,1,0)) status2,
from table
group by batch

Community Mohan Dere 9 年前

OP询问一种方法(SUM)是否比另一种(COUNT)有任何性能优势。在一个有26K行的表上运行一个简单的测试表明,COUNT方法明显更快。YMMV。

DECLARE
  CURSOR B IS
     select batch_id
       FROM batch
      WHERE ROWNUM < 2000;

  v_t1  NUMBER;
  v_t2  NUMBER;
  v_c1  NUMBER;
  v_c2  NUMBER;
  v_opn INTEGER;
  v_cls INTEGER;
  v_btc VARCHAR2(100);
BEGIN
-- Loop using SUM
  v_t1 := dbms_utility.get_time;
  v_c1 := dbms_utility.get_cpu_time;
  FOR R IN B LOOP
     FOR R2 IN (SELECT batch_type_code
                     , SUM(decode(batch_status_code, 'CLOSED', 1, 0)) closed
                     , SUM(decode(batch_status_code, 'OPEN', 1, 0)) OPEN
                     , SUM(decode(batch_status_code, 'REWORK', 1, 0)) rework
                  FROM batch
                 GROUP BY batch_type_code) LOOP 
        v_opn := R2.open;
        v_cls := R2.closed;
     END LOOP;
  END LOOP;
  v_t2 := dbms_utility.get_time;
  v_c2 := dbms_utility.get_cpu_time;
  dbms_output.put_line('For loop using SUM:');
  dbms_output.put_line('CPU seconds used: '||(v_c2 - v_c1)/100);
  dbms_output.put_line('Elapsed time: '||(v_t2 - v_t1)/100);

-- Loop using COUNT
  v_t1 := dbms_utility.get_time;
  v_c1 := dbms_utility.get_cpu_time;
  FOR R IN B LOOP
     FOR R2 IN (SELECT batch_type_code
                     , COUNT(CASE WHEN batch_status_code = 'CLOSED' THEN 1 END) closed
                     , COUNT(CASE WHEN batch_status_code = 'OPEN' THEN 1 END) OPEN
                     , COUNT(CASE WHEN batch_status_code = 'REWORK' THEN 1 END) rework
                  FROM batch
                 GROUP BY batch_type_code) LOOP 
        v_opn := R2.open;
        v_cls := R2.closed;
     END LOOP;
  END LOOP;
  v_t2 := dbms_utility.get_time;
  v_c2 := dbms_utility.get_cpu_time;
  dbms_output.put_line('For loop using COUNT:');
  dbms_output.put_line('CPU seconds used: '||(v_c2 - v_c1)/100);
  dbms_output.put_line('Elapsed time: '||(v_t2 - v_t1)/100);
END;
/

这产生了以下输出:

For loop using SUM:
CPU seconds used: 40
Elapsed time: 40.09
For loop using COUNT:
CPU seconds used: 33.26
Elapsed time: 33.34

编辑:这是我用来回答的测试工具 a similar question