如何在while循环中打印HttpResponse,然后为每个循环附加到它上?

视图应返回单个 HTTPResponse . 添加多个 HttpResponse 对象放在一起。

您可以串联字符串并返回单个res

def fight(request):
    out = ""
    while monster.health > 0 and user.health > 0:
        out += 'Player attacked for: %s\n Monster attacked for: %s\n' % (userattack, monsterattack)
    out += 'You are fighting %s\n Player Health: %s \n Monsters Health: %s' % (monster.name, user.health, monster.health)
    return HttpResponse(out)

另一种常见的模式是生成一个字符串列表,然后在末尾连接它们。这可能比串联字符串更快,但我不确定您在这种情况下是否会看到任何明显的区别:

def fight(request):
    out = []
    while monster.health > 0 and user.health > 0:
        out.append('Player attacked for: %s\n Monster attacked for: %s' % (userattack, monsterattack))
    out.append('You are fighting %s\n Player Health: %s \n Monsters Health: %s' % (monster.name, user.health, monster.health)
    return HttpResponse("\n".join(out))

视图仅返回一个响应。您需要的是ajax轮询(简单但效率不高)或websockets(更复杂-查看django频道了解django中的操作方法-但可能对您的应用程序更有效)。