python中块设备文件的查询大小

我找到的最干净的python解决方案是打开设备文件并在最后查找,返回文件偏移量:

def get_file_size(filename):
    "Get the file size by seeking at end"
    fd= os.open(filename, os.O_RDONLY)
    try:
        return os.lseek(fd, 0, os.SEEK_END)
    finally:
        os.close(fd)

基于Linux特定IOCTL的解决方案:

import fcntl
import struct

device_path = '/dev/sr0'

req = 0x80081272 # BLKGETSIZE64, result is bytes as unsigned 64-bit integer (uint64)
buf = ' ' * 8
fmt = 'L'

with open(device_path) as dev:
    buf = fcntl.ioctl(dev.fileno(), req, buf)
bytes = struct.unpack('L', buf)[0]

print device_path, 'is about', bytes / (1024 ** 2), 'megabytes'

当然,其他unix对于req、buf、fmt有不同的值。

试图从另一个答案中适应:

import fcntl
c = 0x00001260 ## check man ioctl_list, BLKGETSIZE
f = open('/dev/sr0', 'ro')
s = fcntl.ioctl(f, c)
print s

我手头没有合适的电脑来测试这个。我很想知道它是否有效:)