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角度2:将json字段提取到数组中

typescript angular

0

koque · 技术社区 · 8 年前

这是我的数据:

[{"category": "Living Room", "vendor": "Flexsteel"},
{"category": "Living Room", "vendor": "Klaussner"},
{"category": "Living Room", "vendor": "Flexsteel"},
{"category": "Living Room", "vendor": "Craftmaster"},
{"category": "Living Room", "vendor": "Craftmaster"}]

我希望生成的数组显示:

[{"vendor": "Flexsteel"},
{"vendor": "Klaussner"},
{"vendor": "Craftmaster"}]

3 回复 | 直到 8 年前

1

2

Markus Kollers 8 年前

试试这个:

const data = [...your data...];

const vendors = data.map(d => {
  return { vendor: d.vendor };
});

2

Faly 8 年前

let data = [
        {"category": "Living Room", "vendor": "Flexsteel"},
        {"category": "Living Room", "vendor": "Klaussner"},
        {"category": "Living Room", "vendor": "Flexsteel"},
        {"category": "Living Room", "vendor": "Craftmaster"}
      ];
let processedData = data.map(dat => ({ vendor: dat.vendor }));

3

2

FAISAL 8 年前

首先,您需要获得供应商,您可以这样获得:

let data = [{"category": "Living Room", "vendor": "Flexsteel"},
            {"category": "Living Room", "vendor": "Klaussner"},
            {"category": "Living Room", "vendor": "Flexsteel"},
            {"category": "Living Room", "vendor": "Craftmaster"}];

// Get all the vendors 
let vendors = data.map(dat => ({ vendor: dat.vendor }));

// Unique Vendors 
let uniqueVendors= Array.from(new Set(vendors.map((x) => JSON.stringify(x))))
                                             .map((y) => JSON.parse(y.toString()));

完整代码段:

let data = [{"category": "Living Room", "vendor": "Flexsteel"},
            {"category": "Living Room", "vendor": "Klaussner"},
            {"category": "Living Room", "vendor": "Flexsteel"},
            {"category": "Living Room", "vendor": "Craftmaster"}];

// Get all the vendors 
let vendors = data.map(dat => ({ vendor: dat.vendor }));

let uniqueVendors= Array.from(new Set(vendors.map((x) => JSON.stringify(x))))
                                             .map((y) => JSON.parse(y.toString()));
                                             
console.log(uniqueVendors)